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lord [1]
3 years ago
7

Which other subatomic particle has the same mass as a neutron

Physics
2 answers:
RideAnS [48]3 years ago
7 0

Answer:

.................... protons :)

leva [86]3 years ago
7 0

Answer:

protons

The two subatomic particles that have the same mass are protons and neutrons.

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How do objects at rest and in motion respond in the presence of an external, unbalanced force?
koban [17]

Explanation:

Objects at rest and in motion respond to the presence of an external unbalanced force by simple changing their magnitude of motion or position.

We have this knowledge from Newtons first law of motion "a body will remain in a state of rest or continue with uniform motion unless if it is acted upon by an external force".

  • When an external force acts on a body at rest, it will change the position of the body or set it motion.
  • For a body in motion, an external force can make they come to rest or change the motion of the body
5 0
3 years ago
Tim adds salt as he starts to heat a pot of water to cook pasta. When the water is boiling, he notices the salt has dissolved
katen-ka-za [31]

Answer:

The salt is dissolved by the water and heat. If the pot isn't boiling, the salt wouldn't dissolve, it would stay undissolved.

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3 years ago
Technological advances are now making it possible to link visible-light telescopes so that they can achieve the same angular res
leonid [27]

Answer: The angle of resolution =47.05°

Explanation:

The angle of resolution represents the resolve power and precision of optical instruments such as the eye, camera and e en a microscope. It is given by the equation:

Sin A = 1.220(W÷D)

Sin A= 1.220(300÷500)

Sin A = 1.220(0.6)

Sin A = 0.732

A= Sin^-1 0.732

A= 47.05°

4 0
3 years ago
Read 2 more answers
Brad is working on a speed problem in physics class. The problem tells him that a girl runs from her house to the park 0.05 km a
Dmitriy789 [7]
It is corecct becasue it 10 s more added from 0.05
7 0
3 years ago
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A stuntwoman is going to attempt a jump across a canyon that is 77 m wide. The ramp on the far side of the canyon is 25 m lower
liq [111]

initial speed of the stuntman is given as

v = 28 m/s

angle of inclination is given as

\theta = 15 degree

now the components of the velocity is given as

v_x = 28 cos15 = 27.04 m/s

v_y = 28 sin15 = 7.25 m/s

here it is given that the ramp on the far side of the canyon is 25 m lower than the ramp from which she will leave.

So the displacement in vertical direction is given as

\delta y = -25 m

\delta y = v_y * t + \frac{1}{2} at^2

-25 = 7.25 * t - \frac{1}{2}*9.8* t^2

by solving above equation we have

t = 3.12 s

Now in the above interval of time the horizontal distance moved by it is given by

d_x = v_x * t

d_x = 27.04 * 3.12 = 84.4 m

since the canyon width is 77 m which is less than the horizontal distance covered by the stuntman so here we can say that stuntman will cross the canyon.

5 0
3 years ago
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