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2 years ago

CIAMELCH Rearrange spelling

Physics

1 answer:

saveliy_v [14]2 years ago

4 0

I think the answer to this is chemical

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A 700 g can of beans is dropped from a shelf that is 1.5 m high. What is the gravitational potential energy of this can? Round y

OLga [1]

<span>To find the gravitational potential energy of an object, we can use this equation: GPE = mgh m is the mass of the object in kg g = 9.80 m/s^2 h is the height of the object in meters GPE = mgh GPE = (0.700 kg) (9.80 m/s^2) (1.5 m) GPE = 10.3 J The gravitational potential energy of this can is 10.3 J</span>

4 0

3 years ago

Read 2 more answers

A child sits 1.6 m from the center of a merry go round that makes one complete revolution in 4.7 s. What is his angular accelera

olga2289 [7]

Answer: angular acceleration = $2.86\ rad/sec^{2}$

Given:

Distance from center of axis = 1.6 m

Time taken to complete one revolution = 4.7 sec

Therefore, we can evaluate the angular acceleration using the following formula:

$\alpha = r\times \omega^{2}$

$\alpha = r\times (\frac{2\pi}{T})^{2}$

$\alpha = 1.6\times (\frac{2\times3.14}{4.7})^{2}$

$\alpha$ = $2.86\ rad/sec^{2}$

7 0

3 years ago

A negatively charged particle is moving to the right, directly above a wire have a current flowing to the right. In which direct

Varvara68 [4.7K]

Answer:

C) upward

Explanation:

The problem can be solved by using the right-hand rule.

First of all, we notice at the location of the negatively charged particle (above the wire), the magnetic field produced by the wire points out of the page (because the current is to the right, so by using the right hand, putting the thumb to the right (as the current) and wrapping the other fingers around it, we see that the direction of the field above the wire is out of the page).

Now we can apply the right hand rule to the charged particle:

- index finger: velocity of the particle, to the right

- middle finger: direction of the magnetic field, out of the page

- thumb: direction of the force, downward --> however, the charge is negative, so we must reverse the direction --> upward

Therefore, the direction of the magnetic force is upward.

3 0

3 years ago

In a certain time period a coil of wire is rotated from one orientation to another with respect to a uniform 0.38-T magnetic fie

Evgesh-ka [11]

Answer:

8.4 V

Explanation:

induced emf, e1 = 5.8 V

Magnetic field, B1 = 0.38 T

magnetic field, B2 = 0.55 T

induced emf, e2 = ?

As we know that the induced emf is directly proportional to the magnetic field strength.

When the other parameters remains constant then

$\frac{e_{1}}{e_{2}}=\frac{B_{1}}{B_{2}}$

$\frac{5.8}{e_{2}}=\frac{0.38}{0.55}$

e2 = 8.4 V

Thus, the induced emf is 8.4 V.

4 0

2 years ago

A pool ball is rolling at a velocity of 12 cm/s to the right when it is hit by another ball. It continues moving right at a velo

madam [21]

Answer:

Explanation:

Acceleration = rate of change in velocity

a = (21-12)/(0.45) = 20cm/s^2

6 0

3 years ago