Answer:
Explanation:
Left block is on surface with higher inclination so it will go down . If T be tension
For motion of block A ,
net force = mgsin60 - (T + mg cos 60 x μ ) , μ is coefficient of friction .
ma = mgsin60 - T - mg cos 60 x .1
10a = 277.13 - T - 16
= 261.13 - T
T = 261.13 - 10a
For motion of block B
T - mg sin30 - mgcos30 x μ = ma
T- 160 - 27.71 = 10 a
261.13 - 10a - 160 - 27.71 = 10a
73.42 = 20a
a = 3.67 ft / s²
common acceleration = 3.67 ft / s²
Answer:
Utilization, effects
Explanation:
The conductors that carry the current to electrical devices and utilization equipment are the heart of all electrical systems. There are associated effects whenever current flows through a conductor.
Explanation:
- Initial velocity (u) = 10 m/s
- Final velocity (v) = 30 m/s
- Mass (m) = 2400 kg
- Force (F) = 12000 N
Let us find the time taken first.
→ F = ma
- Acceleration (a) = (v – u)/t
→ 12000 = 2400 × (30 – 10)/t
→ 12000 ÷ 2400 = (20)/t
→ 5 = 20/t
→ 5t = 20
→ t = 20 ÷ 5
→ <u>t</u><u> </u><u>=</u><u> </u><u>4</u><u> </u><u>seconds</u>
Now, find the acceleration.
→ a = (v – u)/t
→ a = (30 – 10)/4
→ a = 20/4
→ <u>a</u><u> </u><u>=</u><u> </u><u>5</u><u> </u><u>m</u><u>/</u><u>s²</u>
Now, by using the third equation of motion,
→ v² – u² = 2as
→ (30)² – (10)² = 2 × 5 × s
→ 900 – 100 = 10s
→ 800 = 10s
→ 800 ÷ 10 = s
→ <u>8</u><u>0</u><u> </u><u>m</u><u> </u><u>=</u><u> </u><u>s</u>
Therefore, distance travelled is 80 m.
