3 years ago

Evaluate 4m+23+np−3, when m=7, n=2, and p=8.

Mathematics

2 answers:

Nataly [62]3 years ago

5 0

4(7)+23+(2)(8)-3

28+23+16-3

51+13

Ivahew [28]3 years ago

4 0

The answer is 64 you just plug the numbwrs in and multiple them together and follow the order given

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Svetllana [295]

Answer:

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Step-by-step explanation:

Circumference=2πr where r=16 inches

C=2(3.14)(16)

C=100.5 inches

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Find the equation of the line passing<br> through the points (2, 4) and (3, 2).<br> y = [? ]x + [ ]

PtichkaEL [24]

Answer:

first find slope m

m=(4-2)/(2-3)

m= -2

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If a person takes a prescribed dose of 10 milligrams of Valium, the amount of Valium in that person's bloodstream at any time ca

aleksandr82 [10.1K]

Answer:

(a)8.0mg

(b)36.87 hours

(c)-0.168

Step-by-step explanation:

The amount of Valium in that person's bloodstream at any time can be modeled with the exponential decay function $A ( t ) = 10 e^{ -0.0188 t$ (t in hours)

(a)After 12 Hours

$A ( 12) = 10 e^{ -0.0188*12}\\=7.98\\\approx 8.0 mg $(to the nearest tenth of a milligram)$

(b)If A(t)=5mg

Then:

$5= 10 e^{ -0.0188 t}\\$Divide both sides by 10\\0.5=e^{ -0.0188 t}\\$Take the natural logarithm of both sides\\ln (0.5)=-0.0188 t\\t=ln (0.5) \div (-0.0188)\\$t=36.87 hours (to two decimal places.)$

(c)

$A ( t ) = 10 e^{ -0.0188 t}\\A'(t)=10(-0.0188)e^{ -0.0188 t}\\A'(t)=-0.188e^{ -0.0188 t}\\$At 6 hours, the rate at which the amount of Valium is decaying therefore is:\\A'(6)=-0.188e^{ -0.0188*6}\\$=-0.168 ( to three decimal places)$

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3 years ago

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elena55 [62]

3.14•10^2
3.14•100
A=314cm

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