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olganol [36]
3 years ago
10

HELPPPPPPPPPPPP and explain

Mathematics
1 answer:
Flura [38]3 years ago
4 0
Start by eliminating anything with a z in it. z to the zero power is 1. That means that the top one and the third one from the bottom is gone.

If you want to remove the power (3/4) the rule is that you multiply every power inside the brackets by 3/4.
2 has a power of 1 
2^1 is the way you think of it.
(2^1)^3/4 = 2^(3/4). It would look like this.2^\frac{3}{4}


(a ^2 ) ^(3/4) = 2^(6/4) which would look like this a^\frac{6}{4}
which could be written as a^\frac{3}{2} or a^1.5

x ^ (-5) can be written as x^\frac{-15}{4} Notice that - 5 * 3/4 = - 15/4 It could also be written as 1/x^(15/4) That would get rid of the - sign. 

(y ^ 8) ^(3/4) = y^(24/4) = y^6

On your page, number the questions from a to h

e is the only one I found to be correct.  I will go through the errors. Sometimes I did not list them all. There's just too many of them. The key point is that all the powers are multiplied by 1/4. You need 4 letters or numbers to take 1 letter or number outside the root sign.

a
wrong because a should be 6/4 and not 5/4. As noted, this may not be the only error.

b 
is because the y should be y^1 outside the root sign and y^2 inside the root. 

c
is wrong because there should be a y^2 inside the brackets.

d
is wrong 2 should be 8 raised the the 1/4 power. 8^1/4

e
correct but I sure don't like z^0 sitting there.

f
has all kinds of problems. Start with the 268 That is wrong. If you are going to bring 36 inside the root sign, it should be 36^3 which is 44656. y is wrong and so is x. For x you will have to use the -15 somewhere.

g
is wrong. The 36 is not to be altered and if it is it must be done as it was in the above question
y should be to the 6/4

h 
is wrong. You lost a y somewhere.

Remark
Up until now, the questions you have asked could have been answered and it would have cleared up any of the problems you have been having. This one is quite different. 

It is extremely long and it supposes that you know the multiplication rule for powers. You must have been been taught something before you tackled this monster. You need to go to a help center if you are in school or ask a tutor if you are not. It is not you that's the problem. It's the question that's the problem. It is very long and there are all sorts of tricks in it. In my opinion, it's not really a fair question without a lot of help. 

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What is the average rate of change of the function over the interval x = 0 to x = 8?
notsponge [240]
To find the average rate of change, use the following formula:

\frac{f(b) - f(a)}{b-a}

a and b represent the values of the interval:

a = 0, b = 8

Simplify the original equation by combining like terms:

2x - 13x = -11x
f(x) = -11x + 5

Plug the interval values into the f(x) equation:

f(0) = -11(0) + 5 = 0 + 5 = 5
f(8) = -11(8) + 5 = -88 + 5 = -83

Plug in these values into the average rate of change formula:

\frac{-83 - 5}{8 - 0} =  \frac{-88}{8} = -11

The average rate of change over this interval is -11.
4 0
3 years ago
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Determine whether the sequence appears to be an arithmetic sequence. If so, find the common difference and the next three terms.
vodka [1.7K]

Answer: it is

Step-by-step explanation: the next numbers are 1.5, 3, 4.5.

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HELP!!!!!!!!!!! Determine the equation of the graph, and select the correct answer below. ​
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The correct answer is

y =  - (x + 2)^{2}  - 4

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The vertex form of the equation of a vertical parabola is given by y= 1/4p(x-h)^2 , where (h, k) is the vertex of the parabola a
matrenka [14]

Answer:

  A. y = -2

  B. A(6, -2)

  C. use the midpoint tool to locate the vertex B(6, 1) halfway between F and A

  D. up

  E. divide 6 by 2; positive

  F. 3

  G. y = (1/12)(x -6)² +1

  H. see attached

Step-by-step explanation:

A. The horizontal line 6 units below a point with y-coordinate 4 will be at ...

  y = 4 -6

  y = -2

__

B. The point of intersection will have the same x-coordinate as the focus (6) and the same y-coordinate as the line (-2). That point is A(6, -2).

__

C. As with every other point on the parabola, the vertex is the same distance from the focus as it is from the directrix. It will be the midpoint of segment FA. The vertex is B(6, 1).

__

D. The focus is "inside" the parabola. The focus is above the directrix, so the parabola opens upward, away from the directrix.

__

E, F. We're told to locate the directrix 6 units below the focus. The value of p is half that distance, 3 units. It can also be found by using GeoGebra to measure the length of segment FB.

__

G. Using the vertex form equation with p=3, (h, k) = (6, 1), the equation of the parabola is ...

  y=\dfrac{1}{4p}(x-h)^2+k=\dfrac{1}{4\cdot 3}(x -6)^2+1\\\\\boxed{y=\dfrac{1}{12}(x-6)^2+1}

__

H. see the attachment

__

I. Multiplying the above equation by 12 and eliminating parentheses, we have ...

  12y = x^2 -12x +36 +12

  -48 = x^2 -12x -12y . . . . . . . subtract 48+12y

This is the same equation as shown by GeoGebra.

5 0
4 years ago
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Kisachek [45]

Answer:

Step-by-step explanation:

answer is B (.50) because it went from 1 to 1.5 to 2 to 2.5 , that means you are adding .5 everytime

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