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kirill115 [55]
3 years ago
13

Name

Chemistry
1 answer:
denis-greek [22]3 years ago
6 0

Answer: 1. Asexual 2. Sexual 3. Sexual 4. Both, they're hermaphrodites

Explanation:

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A student mixes in a test tube 3.00mL of 0.050M CuSO4with 7.00mL of 0.20M NH3/NH41 . The solution becomes a deep blue color. Ass
valkas [14]

Answer:

\large \boxed{\text{0.0035 mol/L}}

Explanation:

We are given the volumes and concentrations of two reactants, so this is a limiting reactant problem.

We know that we will need moles, so, lets assemble all the data in one place.

                   Cu²⁺ + 4NH₃ ⟶ Cu(NH₃)₄²⁺

    V/mL:   3.00      7.00

c/mol·L⁻¹:  0.050   0.20

1. Identify the limiting reactant

(a) Calculate the moles of each reactant  

\text{Moles of Cu}^{2+}= \text{3.00 mL solution} \times \dfrac{\text{0.050 mmol Cu}^{2+}}{\text{1 mL solution}} = \text{0.150 mmol Cu}^{2+}\\\\\text{Moles of NH}_{3} = \text{7.00 mL solution} \times \dfrac{\text{0.20 mmol NH}_{3}}{\text{1 mL solution}} = \text{0.140 mmol NH}_{3}

(b) Calculate the moles of Cu(NH₃)₄²⁺ that can be formed from each reactant

(i) From Cu²⁺

\text{Moles of Cu(NH$_{3}$)$_{4}$$^{2+}$} = \text{0.150 mmol Cu}^{2+} \times \dfrac{\text{1 mmol Cu(NH$_{3}$)$_{4}$$^{2+}$}}{\text{1 mmol Cu}^{2+}}\\\\= \text{0.150 mmol Cu(NH$_{3}$)$_{4}$$^{2+}$}

(ii) From NH₃

\text{Moles of Cu(NH$_{3}$)$_{4}$$^{2+}$} = \text{0.140 mmol NH}_{3} \times \dfrac{\text{1 mmol Cu(NH$_{3}$)$_{4}$$^{2+}$}}{\text{4 mmol NH}_{3}}\\\\= \text{0.0350 mmol Cu(NH$_{3}$)$_{4}$$^{2+}$}

NH₃ is the limiting reactant, because it forms fewer moles of the complex ion.

(c) Concentration of the complex ion

\text{The reaction forms 0.0350 mmol Cu(NH$_{3}$)$_{4}$$^{2+}$ in a total volume of 10.00 mL.}\\c = \dfrac{\text{moles}}{\text{litres}} = \dfrac{\text{0.0350 mmol}}{\text{10.00 mL}} = \textbf{0.0035 mol/L}\\\\\text{The concentration of the complex ion is $\large \boxed{\textbf{0.0035 mol/L}}$}

7 0
3 years ago
What is the symbol for aluminum and sulphur ?​
borishaifa [10]
<h2><em>Al2 S3</em></h2>

<em><u>The formula for aluminum sulfide is Al2 S3.</u></em>

<h2><em>hope it helps</em><em>!</em></h2>
4 0
3 years ago
Read 2 more answers
While running, leg muscles work to move leg bones, and the skin helps to
Greeley [361]

Answer:regulating body temperature

Explanation:

5 0
3 years ago
1. Which member of each pair is more stable? a. 2-Methyl-1-butene or 3-Methyl-1-butene b. 2-Methyl-1-butene or 2-Methyl-2-butene
Natasha_Volkova [10]

Answer:

c. 2-dimethyl-2-butene or 3-dimethyl-1-butene

6 0
3 years ago
if the piece of paper is cut in half over and over again, will there ever be a point at which it is no longer paper? explain you
Alisiya [41]

Answer:

No, cutting paper is a physical change. Meaning that it is still paper no matter how many times you cut it. its chemical properties have not changed and it is still paper. cutting it would just give you smaller pieces of paper.

4 0
4 years ago
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