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kvasek [131]
2 years ago
11

Please help! Calculate the percent by mass of water in FeCl2 · 4H20.

Chemistry
1 answer:
Sedaia [141]2 years ago
5 0

Answer:

36.23 %

Explanation:

Let's <em>assume we have 1 mol of FeCl₂ · 4H₂O</em>. In that case we would have:

  • 1 mol of FeCl₂, weighing 126.75 g (that's the molar mass of FeCl₂), and
  • 4 moles of H₂O, weighing (4 * 18 g/mol) 72 g.

Now we can <u>calculate the percent by mass of water</u>:

  • % mass = mass of water / total mass * 100%
  • % mass = \frac{72}{72+126.75} * 100% = 36.23 %
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Answer:

a

Explanation:

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3 years ago
Federico has two samples of pure water—sample X and sample Y. Sample X has a volume of 1 L, and sample Y has a volume of 10 L. H
Lostsunrise [7]

Answer:

The boiling point of sample X and sample Y are exactly the same.

Explanation:

The difference between sample X and sample Y is that they occupy different volumes. However, they both contain pure water. Remember that pure water has uniform composition irrespective of its volume.

Volume does not affect the boiling point as long as the volume is small enough not to give rise to significant pressure changes in the liquid.

The boiling point of a liquid is the temperature at which the pressure exerted by the surroundings upon a liquid is equaled by the pressure exerted by the vapour of the liquid; under this condition, addition of heat results in the transformation of the liquid into its vapour without raising the temperature.

It can be clearly seen from the above that the volume of a solution of pure water does not affect its boiling point hence sample X and sample Y will have the same boiling point.

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3 years ago
1. Which kingdom is made up of only autotrophs?
Reika [66]

Answer: I believe it's C

Hope this helped<3

Can you please make my answer brainly

3 0
3 years ago
The normal boiling point of a substance is defined to be the temperature at which the liquid phase of the substance is in equili
boyakko [2]

Answer:

ΔSv = 0.1075 KJ/mol.K

Explanation:

Binary solution:

∴ a: solvent

∴ b: solute

in equilibrium:

  • μ*(g) = μ(l) = μ* +RTLnXa....chemical potential (μ)

⇒ Ln (1 - Xb) = ΔG/RT

∴ ΔG = ΔHv - TΔSv

⇒ Ln(1 -Xb) = ΔHv/RT - ΔSv/R

∴ Xb → 0:

⇒ Ln(1) = ΔHv/RT - ΔSv/R

∴ T = T*b....normal boiling point

⇒ 0 = ΔHv/RT*b - ΔSv/R

⇒ ΔSv = (R)(ΔHv/RT*b)

⇒ ΔSv = ΔHv/T*b

∴ T*b = 80°C ≅ 353 K

⇒ ΔSv = (38 KJ/mol)/(353 K)

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3 years ago
Abuse of time and temperature can occur in each of the following ways except: The items are not cooked to the proper internal te
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Holding items in the freezer for too long is not an example of abuse of time and temperature.

<h3>What is abuse of time and temperature?</h3>

Abuse of time and temperature has to do with a situation in which time is used in an improper way or food is not held at the correct temperature ultimately leading to food poisoning.

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Learn more about temperature: brainly.com/question/7510619

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2 years ago
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