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kvasek [131]
2 years ago
11

Please help! Calculate the percent by mass of water in FeCl2 · 4H20.

Chemistry
1 answer:
Sedaia [141]2 years ago
5 0

Answer:

36.23 %

Explanation:

Let's <em>assume we have 1 mol of FeCl₂ · 4H₂O</em>. In that case we would have:

  • 1 mol of FeCl₂, weighing 126.75 g (that's the molar mass of FeCl₂), and
  • 4 moles of H₂O, weighing (4 * 18 g/mol) 72 g.

Now we can <u>calculate the percent by mass of water</u>:

  • % mass = mass of water / total mass * 100%
  • % mass = \frac{72}{72+126.75} * 100% = 36.23 %
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Discussion Questions 1. Given the equilibrium equation for a general reaction, A + B  C + D, explain what happens to the reacta
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Answer:The equilibrium constant for a given reaction is [concentration of products]/[concentration of reactants].

Explanation:

Equilibrium constant=[concentration of products]/[concentration of reactants]

The concentration of reactant  molecules is maximum at time 0 and it  decreases as the reaction proceeds, The concentration of product molecules increases.At equilibrium the concentration of reactants and products are equal.

All the changes would occur in accordance with the LeChateliers principle.

For the given reaction the following changes would occur:

a When CO is removed from the reaction mixture so the reaction would shift towards right that is in forward direction as we are decreasing the concentration of CO so the system would try to increase the concentration of CO and that can happen by more production of CO.

b Since the above reaction is an endothermic reaction so when we would be adding heat to the system that is when we would increase the temperature  the reaction would shift forwards as  more heat energy is absorbed by reactants  to form more products.

c When more CO₂ is added so more amount of reactants are added to the system so the system would try to decrease the amount of reactants that is CO₂ and hence more amount of products would be formed.The reaction would shift in forward direction.

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8 0
3 years ago
How many grams of water are theoretically produced for the following reaction given we have 2.6 moles of HCl and 1.4 moles of Ca
leva [86]

Answer:

The answer to your question is: 6.8 g of water

Explanation:

Data

2.6 moles of HCl

1.4 moles of Ca(OH)2

                           2HCl     +     Ca(OH)2    →        2H2O    +      CaCl2

MW                   2(36.5)               74                       36 g               111 g

                          73g                

                            1 mol of HCl ----------------  36.5 g

                           2.6 mol           --------------    x

                              x = (2.6 x 36.5) / 1   = 94.9 g

                           1 mol of Ca(OH)2 --------------   74 g

                         1.4 mol                  ---------------   x

                            x = (1.4 x 74) / 1  = 103.6 g

Grams of water

                        73 g of HCl ------------------   36g of H2O

                        94.9 g        -------------------    x

                     x = (94.9 x 36) / 73 = 46.8 g of water

6 0
2 years ago
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