Answer:
- C. it is a strong acid since the blue litmus paper turns red and the pH is 1.7
Explanation:
As per table gastric juice has pH of 1.7 which is the strong acid. If you remember, 0-7 range determines acids and litmus paper confirms that by turning red.
So correct choice is C.
Answer:
The first high part is Q4, then the low part is Q7, the following high part is Q6, and the energy moving from the next two high points is Q5.
Explanation:
The first high part is Q4, then the low part is Q7, the following high part is Q6, and the energy moving from the next two high points is Q5 because of the diagram.
The volume of 6.40 grams of O₂ gas at STP is 4.48L (option A). Details about volume can be found below.
<h3>How to calculate volume?</h3>
The volume of a gas can be calculated using the following formula:
p = m/v
Where;
- p = density
- m = mass
- v = volume
According to this question, the mass of O₂ gas at STP is 6.40 grams. The density of the gas at STP is 1.43 g/L.
1.43g/L = 6.4g/V
Volume of O2 = 6.4 ÷ 1.43 = 4.48L
Therefore, the volume of 6.40 grams of O₂ gas at STP is 4.48L.
Learn more about volume at: brainly.com/question/1578538
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B. is pretty false my dude
Answer:
4. 1.18 mol·L⁻¹
14. See below.
Explanation:
4. Dilution calculation
V₁c₁ = V₂c₂
Data:
V₁ = 200 mL; c₁ = 5.6 mol·L⁻¹
V₂ = 950 mL; c₂ = ?
Calculation:
c₂ = c₁ × V₁/V₂
c₂ = 5.6 mol·L⁻¹ × (200/950) = 1.18 mol·L⁻¹
The new concentration is 1.18 mol·L⁻¹
.
14. Boyle's Law graphs
We can write Boyle's Law as
pV = k or p = k/V or V= k/p
p and V are inversely related.
(a) As pressure increases, volume decreases. Thus, a graph of V vs p is a hyperbola.
(b) p = k/V =k(1/V)
1/V = (1/k)p
y = m x + 0
A graph of 1/V vs p is a straight line.
