Please help with this question ASAP!!!! Will give brainliest

Brian buys candy that costs 4 per pound. He will buy at least 8 pounds of candy. What are the possible amounts he will spend on

s2008m [1.1K]

Answer:

32 pound but I dunno what that is in american dollars

8 0

3 years ago

Read 2 more answers

3. The adult men of the Dinaric Alps have the highest average height of all regions. The

ahrayia [7]

Using the normal distribution, it is found that:

3 - a) The 40th percentile of the height of Dinaric Alps distribution for men is of 72.2 inches.

3 - b) The minimum height of man in the Dinaric Alps that would place him in the top 10% of all heights is of 76.84 inches.

4 - a) The 25th percentile for the math scores was of 71.6 inches.

4 - b) The 75th percentile for the math scores was of 78.4 inches.

<h3>Normal Probability Distribution </h3>

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

It measures how many standard deviations the measure is from the mean.

After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

Question 3:

The mean is of 73 inches, hence $\mu = 73$ .

The standard deviation is of 3 inches, hence $\sigma = 3$ .

Item a:

The 40th percentile is X when Z has a p-value of 0.4, so X when Z = -0.253.

$Z = \frac{X - \mu}{\sigma}$

$-0.253 = \frac{X - 73}{3}$

$X - 73 = -0.253(3)$

$X = 72.2$

The 40th percentile of the height of Dinaric Alps distribution for men is of 72.2 inches.

Item b:

The minimum height is the 100 - 10 = 90th percentile is X when Z has a p-value of 0.9, so X when Z = 1.28.

$Z = \frac{X - \mu}{\sigma}$

$1.28 = \frac{X - 73}{3}$

$X - 73 = 1.28(3)$

$X = 76.84$

The minimum height of man in the Dinaric Alps that would place him in the top 10% of all heights is of 76.84 inches.

Question 4:

The mean score is of 75, hence $\mu = 75$ .

The standard deviation is of 5, hence $\sigma = 5$ .

Item a:

The 25th percentile is X when Z has a p-value of 0.25, so X when Z = -0.675.

$Z = \frac{X - \mu}{\sigma}$

$-0.675 = \frac{X - 75}{5}$

$X - 75 = -0.675(5)$

$X = 71.6$

The 25th percentile for the math scores was of 71.6 inches.

Item b:

The 75th percentile is X when Z has a p-value of 0.25, so X when Z = 0.675.

$Z = \frac{X - \mu}{\sigma}$

$0.675 = \frac{X - 75}{5}$

$X - 75 = 0.675(5)$

$X = 78.4$

The 75th percentile for the math scores was of 78.4 inches.

To learn more about the normal distribution, you can take a look at brainly.com/question/24663213

5 0

2 years ago

What is 2 3/5 multiplied by 2 as a mixed number or fraction

Bond [772]

Answer:

5 1/5

Step-by-step explanation:

2 3/5 * 2= 5 1/5

mark brainliest :)

7 0

4 years ago

Mr. Kramer's patio is in the shape of a trapezoid. The trapezoid and its dimensions are shown below. What is the area of the pat

BigorU [14]

Answer:

C 315

Step-by-step explanation:

(12 + 30) * 15/2 = 315

5 0

3 years ago

The abdominopelvic region that is bordered by all four imaginary lines is the

Ainat [17]

Umbilical point.

An umbilic point, likewise called just an umbilic, is a point on a surface at which the arch is the same toward any path.

In the differential geometry of surfaces in three measurements, umbilics or umbilical focuses are focuses on a surface that are locally round. At such focuses the ordinary ebbs and flows every which way are equivalent, consequently, both primary ebbs and flows are equivalent, and each digression vector is a chief heading. The name "umbilic" originates from the Latin umbilicus - navel.

Umbilic focuses for the most part happen as confined focuses in the circular area of the surface; that is, the place the Gaussian ebb and flow is sure. For surfaces with family 0, e.g. an ellipsoid, there must be no less than four umbilics, an outcome of the Poincaré–Hopf hypothesis. An ellipsoid of unrest has just two umbilics.

4 0

3 years ago