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Dennis_Churaev [7]
3 years ago
12

I need helllllpppp? I do know what to do n this one math problem if any of you guys know this I will give you nothing absolutely

nothing.?
Mathematics
1 answer:
ki77a [65]3 years ago
3 0
Whats the math problem??
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The Unit Circle
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Answer:

B

Step-by-step explanation:

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3 years ago
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Sara claims that a sequence of transformations carries Rectangle 1 onto Rectangle 2. Which of the following sequences of transfo
Anastasy [175]
Wait isn’t it a? I’m not sure tho
8 0
3 years ago
Kristi invests $3,000 at a 7.25% annual simple interest rate, and her sister Kari invests $3,200 at a 6.25% annual simple intere
True [87]

Answer:

Kristi

Step-by-step explanation:

The formula for Simple Interest =

Principal × Rate × Time

For Kristi

Kristi invests $3,000 at a 7.25% annual simple interest rate,

Principal = $3000

Rate = 7.25% = 0.0725

Time = 1

Simple interest = $3000 × 0.0725 × 1

= $217.5

For Kari

Her sister Kari invests $3,200 at a 6.25% annual simple interest rate.

Principal = $3200

Rate = 6.25% = 0.0625

Time = 1

Simple interest = $3200 × 0.0625 × 1

= $200

From the above calculation, we can see that: Kristi will earn the greater amount of interest after one year

3 0
3 years ago
A recipe requires 1/2 cup of sugar for every batch of cakes. How batches of cakes can be made with 5 1/2 cups of sugar?
Sedaia [141]

Answer:

11

Step-by-step explanation:

5.5/.5 = 11

7 0
3 years ago
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Pls solve the simultaneous equation in the attachment.
siniylev [52]

Answer:

Part a) The solution is the ordered pair (6,10)

Part b) The solutions are the ordered pairs (7,3) and (15,1.4)

Step-by-step explanation:

Part a) we have

\frac{x}{2}-\frac{y}{5}=1 ----> equation A

y-\frac{x}{3}=8 ----> equation B

Multiply equation A by 10 both sides to remove the fractions

5x-2y=10 ----> equation C

isolate the variable y in equation B

y=\frac{x}{3}+8 ----> equation D

we have the system of equations

5x-2y=10 ----> equation C

y=\frac{x}{3}+8 ----> equation D

Solve the system by substitution

substitute equation D in equation C

5x-2(\frac{x}{3}+8)=10

solve for x

5x-\frac{2x}{3}-16=10

Multiply by 3 both sides

15x-2x-48=30

15x-2x=48+30

Combine like terms

13x=78

x=6

<em>Find the value of y</em>

y=\frac{x}{3}+8

y=\frac{6}{3}+8

y=10

The solution is the ordered pair (6,10)

Part b) we have

xy=21 ---> equation A

x+5y=22 ----> equation B

isolate the variable x in the equation B

x=22-5y ----> equation C

substitute equation C in equation A

(22-5y)y=21

solve for y

22y-5y^2=21

5y^2-22y+21=0

Solve the quadratic equation by graphing

The solutions are y=1.4, y=3

see the attached figure

<em>Find the values of x</em>

For y=1.4

x=22-5(1.4)=15

For y=3

x=22-5(3)=7

therefore

The solutions are the ordered pairs (7,3) and (15,1.4)

3 0
4 years ago
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