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Angelina_Jolie [31]
3 years ago
11

Which quantity is a scalar quantity

Physics
2 answers:
ruslelena [56]3 years ago
8 0
Length, or option C is the correct answer, since it does not have direction, just magnitude, hence forth a scalar quantity.
Naya [18.7K]3 years ago
3 0
Vectors have magnitude and direction, scalars<span> only have magnitude.</span>
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How many significant figures are there in : (a) 0.000054 (b) 3.001 x 10^5 (c) 5.600
melomori [17]

Answer:

(a) 2 (b) 4 (c) 4

Explanation:

Significant figures : The figures in a number which express the value -the magnitude of a quantity to a specific degree of accuracy is known as significant digits.

Rules for significant figures:

  • Digits from 1 to 9 are always significant and have infinite number of significant figures.
  • All non-zero numbers are always significant. For example: 654, 6.54 and 65.4 all have three significant figures.
  • All zero’s between integers are always significant. For example: 5005, 5.005 and 50.05 all have four significant figures.
  • All zero’s preceding the first integers are never significant. For example: 0.0078 has two significant figures.
  • All zero’s after the decimal point are always significant. For example: 4.500, 45.00 and 450.0 all have four significant figures.
  • All zeroes used solely for spacing the decimal point are not significant. For example : 8000 has one significant figure.

As per question,

0.000054 has 2 significant figures.

3.001 x 10⁵ has 4 significant figures.

5.600 has 4 significant figures.

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3 years ago
A 2 N and an 8 N force pull on an object to the right and a 4 N force pulls on the same object to the left. If the object has a
Elden [556K]

Answer:

a = 12 [m/s²]

Explanation:

To solve this problem we must use Newton's second law which tells us that the sum of forces on a body is equal to the product of mass by acceleration.

ΣF = m*a

where:

ΣF = sum of forces acting on a body [N] (units of Newtons)

m = mass = 0.5 [kg]

a = acceleration [m/s²]

Let's take the direction of positive forces to the right and negative forces directed to the left

2 + 8 - 4 = 0.5*a

6 = 0.5*a

a = 12 [m/s²]

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