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mrs_skeptik [129]
3 years ago
6

What are the two main processes carried out by the excretory system?​

Physics
1 answer:
Paha777 [63]3 years ago
5 0
Water and carbon dioxide
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Solve this question with explanation <br> Best answer will be brainliest <br> 40 points given
Yuliya22 [10]

Answer:

12 km/h

Explanation:

Average Speed = Distance / Time (or rate)

Pick a point on the graph for Ian and plug in values.

For example, 20 minutes -> 4km

Hence, Average speed = 4km ÷ 20 minutes = 0.2 km/min

0.2 km/min × 60 = 12 km/h

7 0
3 years ago
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The cabinet is mounted on coasters and has a mass of 45 kg. The casters are locked to prevent the tires from rotating. The coeff
stira [4]

Answer:

the force P required for impending motion is 132.3 N

the largest value of "h" allowed if the cabinet is not to tip over is 0.8 m

Explanation:

Given that:

mass of the cabinet  m = 45 kg

coefficient of static friction μ =  0.30

A free flow body diagram illustrating what the question represents is attached in the file below;

The given condition from the question let us realize that ; the casters are locked to prevent the tires from rotating.

Thus; considering the forces along the vertical axis ; we have :

\sum f_y =0

The upward force and the downward force is :

N_A+N_B = mg

where;

\mathbf { N_A  \ and  \ N_B} are the normal contact force at center point A and B respectively .

N_A+N_B = 45*9.8

N_A+N_B = 441    ------- equation (1)

Considering the forces on the horizontal axis:

\sum f_x = 0

F_A +F_B  = P

where ;

\mathbf{ F_A \ and \ F_B } are the static friction at center point A and B respectively.

which can be written also as:

\mu_s N_A + \mu_s N_B  = P

\mu_s( N_A +  N_B)  = P

replacing our value from equation (1)

P = 0.30 ( 441)    

P = 132.3 N

Thus; the force P required for impending motion is 132.3 N

b) Since the horizontal distance between the casters A and B is 480 mm; Then half the distance = 480 mm/2 = 240 mm = 0.24 cm

the largest value of "h" allowed for  the cabinet is not to tip over is calculated by determining the limiting condition  of the unbalanced torque whose effect is canceled by the normal reaction at N_A and it is shifted to N_B:  

Then:

\sum M _B = 0

P*h = mg*0.24

h =\frac{45*9.8*0.24}{132.3}

h = 0.8 m

Thus; the largest value of "h" allowed if the cabinet is not to tip over is 0.8 m

6 0
3 years ago
What is the relationship between gravity and pressure in a nebula?
zheka24 [161]
The relationship between gravity and pressure in a nebula is that pressure balances gravity.  <span>The </span>pressure<span> exerted by a static fluid depends only upon the depth of the fluid, the density of the fluid, and the acceleration of </span><span>gravity. The answer is B. </span>
8 0
3 years ago
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Spaceships A and B are traveling directly toward each other at a speed 0.5c relative to the Earth, and each has a headlight aime
Rainbow [258]
The answer is 2) 1.0c. Light will always propagate through a vacuum at the speed of light “c”; even when moving at a significant fraction of the speed of light, observers will still measure this as the speed of light and the difference is resultant of time dilation.
5 0
3 years ago
IP Force to Hold a Baseball A person holds a 1.42-N baseball in his hand, a distance of 34.0 cm from the elbow joint, as shown i
mixer [17]

We will assume that the CM of the arm is at "L" from the elbow, and the ball is at 34cm. Then the net torque is computed by:


Net τ = 1.42 N * 34 cm + 1.50 kg * 9.8m/s² * 34 cm/2 – 12.6 N*2.75cm 

= 48.28 N*cm + 1.50kg * 9.8m/s² * 34 cm/2 – 12.6 N*2.75cm 

= 48.28 N*cm + 499.8 – 34.65 N*cm

τ  = 513.43 N*cm or 5.1343 N*m

6 0
3 years ago
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