Question

There is a large box and a small box on a table. The same force is applied to both boxes. The large box moves two feet and the small box moves one foot. Which movement shows the most work done?
The movement of the large box shows more work because the box moved a longer distance.

The work done is equal because the same force was applied to both boxes.

The movement of the small box shows more work because the box moved a shorter distance.

The work done was equal because both boxes moved in the same direction as the force.

Answer 1

The best and most correct answer among the choices provided by your question is the first choice.

The movement of the large box shows more work because the box moved a longer distance.

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Answer 2

Explanation :

We know that the work done by an object depends directly on the applied force, displacement caused due to that force and on the angle between the force and the displacement.

Mathematically, it is written as :

$W=Fdcos\theta$

Where,

F is the applied force

d is the displacement or distance.

So, the work done is directly proportional to distance.

In this case, she same force is applied to both boxes. The large box moves two feet and the small box moves one foot.

So, the movement of the large box shows more work because the box moved a longer distance.

Hence, the correct option is (a).