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3 years ago

9

what happens when light travels from one medium to another with a different index of refraction at a zero degree angle of incide

nce?

2 answers:

Brut [27]3 years ago

8 0

Answer:

If the index of refraction of the medium is greater, the light slows down.

zaharov [31]3 years ago

4 0

Answer:

No Refraction takes places

Explanation:

When light travels from one medium to another at an angle of incidence 0 degree then no refraction takes place .

It is because according to Refraction law

$n_{i}$ sini = $n_{r}$ sinr

where $n_{i} ,n_{r}$ are the refractive index of medium of incidence and medium of refraction .

When i = 0 , left side of the equation becomes 0 and thus r (angle of refraction) must be zero. So No refraction takes place

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During a tornado in 2008 the Peachtree Plaza Westin Hotel in downtown Atlanta suffered damage. Suppose a piece of glass dropped

Darina [25.2K]

Answer:

Time = t = 6.62 s

Explanation:

Given data:

Height = h = 215 m

Initial velocity = $v_{i}$ = 0 m/s

gravitational acceleration = g = 9.8 m/s²

Time = t = ?

According to second equation of motion

$h = v_{i}t + \frac{1}{2}gt^{2}$

As initial velocity is zero, So the first term of right hand side of above equation equal to zero.

$h = \frac{1}{2}gt^{2}$

t² = $\frac{2h}{g}$

t = $\sqrt{\frac{2h}{g} }$

t = $\sqrt{\frac{(2)(215) }{9.8} }$

t = 6.62 s

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3 years ago

Of the more than 2,000 known minerals approximately 95% of them belong to what mineral group?

Temka [501]

Your answer is Silicates.

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3 years ago

Which of the following shows kinetic energy being converted into potential energy?

Komok [63]

B) a rock being tossed high into the air

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3 years ago

A single-turn current loop, carrying a current of 4.03 A, is in the shape of a right triangle with sides 68.1, 151, and 166 cm.

SashulF [63]

Answer:

Part a)

$F = 0$

Part b)

$F = 0.25 N$

Part c)

$F = 0.25 N$

Part d)

Net force on a closed loop in uniform magnetic field is always ZERO

$F_{net} = 0$

Explanation:

As we know that force on a current carrying wire is given as

$\vec F = i(\vec L \times \vec B)$

now we have

Part a)

current in side 166 cm and magnetic field is parallel

so we have

$F = i(\vec L \times \vec B)$

here we know that L and B is parallel to each other so

$F = 0$

Part b)

For 68.1 cm length wire we have

$F = iLB sin\theta$

here we know that

$cos\theta = \frac{68.1}{166}$

$\theta = 65.8$

so we have

$F = (4.03)(0.681)(99.3 \times 10^{-3})sin65.8$

$F = 0.25 N$

Part c)

For 151 cm length wire we have

$F = iLB sin\phi$

here we know that

$cos\phi = \frac{151}{166}$

$\theta = 24.5$

so we have

$F = (4.03)(1.51)(99.3 \times 10^{-3})sin24.5$

$F = 0.25 N$

Part d)

Net force on a closed loop in uniform magnetic field is always ZERO

$F_{net} = 0$

4 0

3 years ago

Is the relationship between velocity and centripetal force a direct, linear or nonlinear square relationship?

Svet_ta [14]

Answer:

non linear square relationship

Explanation:

formula for centripetal force is given as

a = mv^2/r

here a ic centripetal acceleration , m is mass of body moving in circle of radius r and v is velocity of body . If m ,and r are constant we have

a = constant × v^2

a α v^2

hence non linear square relationship

5 0

3 years ago