At stp conditions (

), the speed of sound is

The sound wave moves by uniform motion, so we can use the basic relationship between space, time and velocity:

where S is the distance covered by the sound wave in a time t. In our problem, t=3.00 s, therefore the distance covered by the sound wave is
He doesn't lose weight he stays the same weight it's just gravity that changes
Answer:
4.13Hz
Explanation:
f1 = 1/t1 = 1/0.022 = 45.45 Hz
f2 = 1/t2 = 1/0.0242= 41.32 Hz
No. of beats
= 45.45- 41.32
~ 4.13Hz
Answer:
V = 90.51 m/s
Explanation:
From the given information:
Initial speed (u) = 0
Distance (S) = 391 m
Acceleration (a) = 18.9 m/s²
Using the relation for the equation of motion:
v² - u² = 2as
v² - 0² = 2as
v² = 2as


v = 121.57 m/s
After the parachute opens:
The initial velocity = 121.57 m/ss
Distance S' = 332 m
Acceleration = -9.92 m/s²
How fast is the racer can be determined by using the relation:


V = 90.51 m/s