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bazaltina [42]
3 years ago
5

Which statement about acids is true? A. Weak acids ionize completely. B. Acids turn red litmus paper blue. C. Acids conduct elec

tricity when dissolved in water. D. Strong acids release hydroxide ions when dissolved in water.
Physics
1 answer:
Vinil7 [7]3 years ago
6 0
Id say d because it releases hydrogen and on the other hand a base receives it
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It must gain an electron because if the proton number was to change it would no longer be the same element.
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4 years ago
A Huge water tank is 2m above the ground if the water level on it is 4.9m high and a small opening is there at the bottom then t
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Answer:

The speed of efflux of non-viscous water through the opening will be approximately 6.263 meters per second.

Explanation:

Let assume the existence of a line of current between the water tank and the ground and, hence, the absence of heat and work interactions throughout the system. If water is approximately at rest at water tank and at atmospheric pressure (P_{atm}), then speed of efflux of the non-viscous water is modelled after the Bernoulli's Principle:

P_{1} + \rho\cdot \frac{v_{1}^{2}}{2} + \rho\cdot g \cdot z_{1} = P_{2} + \rho\cdot \frac{v_{2}^{2}}{2} + \rho\cdot g \cdot z_{2}

Where:

P_{1}, P_{2} - Water total pressures inside the tank and at ground level, measured in pascals.

\rho - Water density, measured in kilograms per cubic meter.

g - Gravitational acceleration, measured in meters per square second.

v_{1}, v_{2} - Water speeds inside the tank and at the ground level, measured in meters per second.

z_{1}, z_{2} - Heights of the tank and ground level, measured in meters.

Given that P_{1} = P_{2} = P_{atm}, \rho = 1000\,\frac{kg}{m^{3}}, g = 9.807\,\frac{m}{s^{2}}, v_{1} = 0\,\frac{m}{s}, z_{1} = 6.9\,m and z_{2} = 4.9\,m, the expression is reduced to this:

\left(9.807\,\frac{m}{s^{2}} \right)\cdot (6.9\,m) = \frac{v_{2}^{2}}{2} + \left(9.807\,\frac{m}{s^{2}} \right)\cdot (4.9\,m)

And final speed is now calculated after clearing it:

v_{2} = \sqrt{2\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (6.9\,m-4.9\,m)}

v_{2} \approx 6.263\,\frac{m}{s}

The speed of efflux of non-viscous water through the opening will be approximately 6.263 meters per second.

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