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belka [17]
3 years ago
10

explain why a circulatory system is important in meeting the needs of all cells throughout an animals body

Physics
1 answer:
Effectus [21]3 years ago
7 0
Helps ur blood circulate, to ur head and ect helpin u leave
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Three forces act on a flange as shown below. Determine the magnitude of the unknown force F (in lb) such that the net force acti
Tems11 [23]

Answer:

The unknown force will be 18.116 lb.

Explanation:

Given that,

Three forces act on a flange as shown in figure.

The net force acting on the flange is a minimum.

\dfrac{dF_{net}}{df}=0

We need to calculate the unknown force

Using formula of net force

\vec{F_{net}}=\vec{F_{x}}+\vec{F_{y}}

Put the value into the formula

\vec{F_{net}}=(F\cos45+70\cos30-40)\hat{i}+(70\sin30-F\sin45)\hat{j}

\vec{F_{net}}=(F\cos45+70\times\dfrac{\sqrt{3}}{2})\hat{i}+(70\times\dfrac{1}{2}-F\sin45)\hat{j}

The magnitude of net force,

F_{net}=\sqrt{F_{x}^2+F_{y}^2}

F_{net}=\sqrt{(F\times\dfrac{1}{\sqrt{2}}+60.62)^2+(35-F\times\dfrac{1}{\sqrt{2}})^2}

F_{net}=\sqrt{F^2+(60.62)^2+121.24\times\dfrac{F}{\sqrt{2}}+(35)^2-70\times\dfrac{F}{\sqrt{2}}}

F_{net}=\sqrt{F^2+4899.78+36.232F}

On differentiating w.r.to F

(\dfrac{dF_{net}}{dF})^2=2F+36.232

0=2F+36.232

F=-\dfrac{36.232}{2}

F=-18.116\ lb

Negative sign shows the direction of force which is downward.

Hence, The unknown force will be 18.116 lb.

6 0
2 years ago
Where is the deepest cave in the world? How far down is it located?
Sergeeva-Olga [200]

Answer:

Geology Notes

1 Veryovkina Cave 2212[1] 13.5 km (8.4 mi)[1] Abkhazia / Georgia 43°23′52″N 40°21′37″E.

6 0
3 years ago
You shake a bottle of soda and take off the cap. If the soda shoots out of the
kicyunya [14]

Answer:

A. 11.5 m

Explanation:

Given,

The initial velocity of the soda cap, u = 15 m/s

The soda bottle cap is projected vertically upwards,

Hence, the angle formed with the ground, Ф = 90°

The maximum height of the projectile is given by the formula,

                                    h_{max} =\frac{u^{2}sin^{2}\phi}{2g}

Substituting the given values in the above equation

                                   h_{max} =\frac{15^{2}sin^{2}90}{2X9.8}

                                                        = 11.5 m

Hence, the maximum height of the cap is h = 11.5 m

8 0
3 years ago
if an object is moving with a velocity of 24m/s and has an acceleration of -4m/s how long will it take to stop
ololo11 [35]
The negative sign on the acceleration is only a vector quantity that means the object is accelerating to the left. Hence, we can only focus on it magnitude which is 4 m/s^2. Acceleration is the change in velocity over time. The change in velocity must be 24 m/s - 0 m/s, if you want the object to stop. Therefore,

a = (v2 - v1)/t
4 = (24 - 0)t
t = 6 seconds

The object will stop after 6 seconds.
7 0
3 years ago
A major artery with a cross sectional area of 1.00cm^2 branches into 18 smaller arteries, each with an average cross sectional a
dybincka [34]

Here we can say that rate of flow must be constant

so here we will have

A_1v_1 = 18 A_2v_2

now we know that

A_1 = 1 cm^2

A_2 = 0.4 cm^2

now from above equation

1 cm^2 v_1 = 18(0.400 cm^2)v_2

\frac{v_2}{v_1} = \frac{1}{18\times 0.4}

\frac{v_2}{v_1} = 0.14

so velocity will reduce by factor 0.14

3 0
3 years ago
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