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stellarik [79]
3 years ago
6

On a velocity vs. time graph, what does it mean when the line crosses over the x-axis?

Physics
1 answer:
Phantasy [73]3 years ago
8 0

On a velocity - time graph, if the line crosses the x - axis it depicts that the object has started moving in the opposite direction.

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With nonreturn to zero signaling, the voltage alternates between zero and a positive or negative voltage. True False
SSSSS [86.1K]

Answer:

False.

Explanation:

No. Voltage does not alternate between zero and positive or negative. In non return signaling (NRZ) voltage at zero represents the 0 bit and at the positive represent the 1 bit. NRZ is one of the signal levels of uni polar Scheme in which the signal does not return to zero at the middle of it. For example 10110. That is why it named as the non return signaling.

7 0
3 years ago
A 16.0 m long, thin, uniform metal rod slides north at a speed of 21.0 m/s. The length of the rod maintains an east-west orienta
Gekata [30.6K]

Answer:

14.112 mV

Explanation:

L = 16 m, v = 21 m/s, B = 42 μ T = 42 x 10^-6 T

The formula for the induced emf is given by

e = B x v x L

e = 42 x 10^-6 x 21 x 16 = 14.112 x 10^-3 V = 14.112 mV

Thus, the induce emf is 14.112 mV.

4 0
3 years ago
The International Space Station (ISS) orbits Earth in a nearly circular orbit that is 345 km above Earth's surface.
Tems11 [23]

Answer:

1) v = 7.70 10³ m/s , 2) F = 115 N and 3)    (F/W)% = 90.2%

Explanation:

1) To solve the problem let's use Newton's second law where force is gravitational force and acceleration is centripetal

    F = ma.

    F = G m M / r²

    a = v² / r

    G m M / r² = m v² / r

    G M / r = v²

Let's look for the distance is the distance from the surface of the has to the station 345 103 m plus the radius of the Earth

    r = Re + 345 103

    r = 6.37 10⁶ + 3.45 10⁵

    r = 6.715 10⁶ m

Let's calculate the speed

   v = √ (6.67 10⁻¹¹ 5.98 10²⁴ / 6,715 10⁶) = √ (59,399 10⁶)

   v = 7.70 10³ m/s

The speed module is constant, so we can use the uniform motion relationships

   v = d / t

The distance is the length of the circle

   d = 2π r

   d = 2π 6.715 106

   d = 42.2 10⁶ m

Let's calculate the time

   t = d / v

   t = 42.2 10⁶ / 7.70 10³

   t = 5.48 10³ s

2) Let's use the universal gravitation equation

   F = G m M / r²

   F = 6.67 10⁻¹¹ 13.0  5.98 10²⁴ /(6.715 10⁶)²

   F = 11.5 10¹ N

   F = 115 N

3) in this for we are asked the relationship is out with the weight of the body on earth

   F / W = F / mg

   F / W = 115 / (13.0  9.8)

   F / W = 0.902

  F / W% = 90.2%

5 0
3 years ago
HELP ME!!!!!!!!!!!!! DUE IN 10 MINUTES HURRY!!!!!!!
alexandr1967 [171]

Answer:

3.4 or 3 11/23

Explanation:

just dive so you can see it as if it were Evelyn distributed

7 0
3 years ago
Read 2 more answers
Billiard ball A strikes another ball B of the same mass, which is at rest, such that after the impact they move at angles ΘA and
Drupady [299]

Answer:

7.6427m/s

Explanation:

Given:v_a=4.7m/s, \theta_a=33.0\textdegree and \ v_b=4.5m/s

#Applying the conservation of momentum along the x-axis:mv_i=mv_acos\theta_a+mv_bcos\theta_b

#And along y-axis:

0=-sin\theta_a+mv_bsin\theta_b

#Solving  for \theta_b:

sin\rheta_b=\frac{v_a}{v_b}sin\theta_a=4.7/4.5\times sin33.0\textdegree\\=0.5688\\\therefore \theta_b=34.67\textdegree

#By substitution in the x-axis equation:

v_i=4.7cos 33.0\textdegree +4.5cos 34.67\textdegree\\=7.6427m/s

Hence the original speed of the ball before impact is 7.6427m/s

4 0
3 years ago
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