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Serga [27]
3 years ago
9

How can exponents help you to find the area of a rectangle if each side length is multiplied by X

Mathematics
1 answer:
Phantasy [73]3 years ago
4 0
Umm I can't really explain but like everyone knows that a rectangle had four sides so if each side is multiplied by x then it's going to be that number to the fourth power because you know 4 sides four x's but I not 100% sure just wanted to help out
You might be interested in
A car dealership has 240 cars in the parking lot and 17.5% of them are red. Of the other 6 colors in the lot each color has the
SIZIF [17.4K]
Answer:
33

Explanation:
number of red cars
17.5
%
×
240
=
42

number of cars of other colors
=
240
−
42
=
198

number of black cars
1
6
×
198
=
33
3 0
4 years ago
Michael weighed 186 pounds. His doctor put him on a diet which enabled him to lose 3 pounds per month. What was his weight after
Amiraneli [1.4K]
His weight will be 165 pounds.
186- (3 x 7)= 165 pounds 
6 0
4 years ago
2) 2.25 is 62.5% of what number?
IrinaK [193]

Answer:

250

Step-by-step explanation:

250 ÷ 400 = 0.625 = 0.625 × 100/100 = (0.625 × 100)/100 = 62.5/100 = 62.5% Answer: Percentage of 62.5% of what number = 250?

6 0
3 years ago
Read 2 more answers
Help !!!!! Also show me how to do it if you can guys
natali 33 [55]

Answer:

D.

Step-by-step explanation:

A is linear, you can figure out that y=x+5

B is linear, y=22(x+1)

C is linear, y=8x+5

D is exponential, y=3ˣ⁺¹

Deriving these formulas is a matter of trial and error if you know you can choose between linear and exponential.

5 0
3 years ago
Read 2 more answers
In 2012 your car was worth $10,000. In 2014 your car was worth $8,800. Suppose the value of your car decreased at a constant rat
Sonbull [250]

Answer:

g(t) = 10000(0.938)^t

Step-by-step explanation:

Given data:

car worth is $10,000 in 2012

car worth is $8000 in 2014

let linear function is given as

P(t) = at + b

which denote the value of car in year t

take t =0 for year 2012

at t =0, 10,000 = 0 + b

we get b = 10,000

take t =2 for year 2014

at t =2, P(2) = 2a + b

8800 = 2a + 10,000

a = - 600

Thus the price of car at year t after 2012 is given as p(t) = -600t + 10000

let the exponential function p(t)  =ab^2 where t denote t = 0 at 2012

putting t = 0 P(0) = 10,000 we get 10,000 = ab^0

a = 10,000

putting t = 2 p = 8800

8800 =ab^2

b^2 = \frac{8800}{10000}

b = 0.938

g(t) = 10000(0.938)^t

3 0
4 years ago
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