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3 years ago

A red kangaroo hops at an average speed of 20km per hour. How fast is this in meters per minute?

Mathematics

1 answer:

masya89 [10]3 years ago

8 0

Answer:

333.3 meters per minute

Step-by-step explanation:

The best way to solve this problem is using dimensional anaysis. First, we write out our starting units, that being 20km/1hr. We have to keep in mind that we want to change the kilometers to meters and the hours to minutes.

$\frac{20km}{1hr}$

We know that there are 1000 meters in 1 kilometer. We add this to the dimensional analysis as 1000m/1km. We write it as this because we want the kilometers to cancel each other out. We only want the meters.

$= \frac{20km}{1hr} *\frac{1000m}{1km} ...$

We also know that 1 hour is 60 minutes. We add this to the analysis as well so that the hours cancel each other.

$= \frac{20km}{1hr} *\frac{1000m}{1km} * \frac{1hr}{60min}$

We now solve this expression. Since both the kilometers and the hours cancel out, we have meters per minute as our unit. All that's left are the numbers.

= (20*1000*1)/(1*1*60) m/min

= 333.3 meters per minute

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11111111111111111111111

Nat2105 [25]

Answer:

1) Zero based on (-16·t - 2) is t = -1/8 second

2) Zero based on (t - 1) is t = 1 second

Step-by-step explanation:

The given functions representing the height of the beach ball the child throws as a function of time are;

y = (-16·t - 2)·(t - 1) and y = -16·t² + 14·t + 2

We note that (-16·t - 2)·(t - 1) = -16·t² + 14·t + 2

Therefore, the function representing the height of the beachball, 'y', is y = (-16·t - 2)·(t - 1) = -16·t² + 14·t + 2

The zeros of a function are the values of the variables, 'x', of the function that makes the value of the function, f(x), equal to zero

In the function of the question, we have;

y = (-16·t - 2)·(t - 1) = -16·t² + 14·t + 2

The above equation can be written as follows;

y = (-16·t - 2) × (t - 1)

Therefore, 'y' equals zero when either (-16·t - 2) = 0 or (t - 1) = 0

1) The zero based on (-16·t - 2) = 0, is given as follows;

(-16·t - 2) = 0

∴ t = 2/(-16) = -1/8

t = -1/8 second

The zero based on (-16·t - 2) is t = -1/8 second

2) The zero based on (t - 1) = 0, is given as follows;

(t - 1) = 0

∴ t = 1 second

The zero based on (t - 1) is t = 1 second

4 0

3 years ago

Expand and combine like terms. (4b^2+ 3) (4b^2- 3) = 1 SEE ANSWER

krok68 [10]

Answer:

Step-by-step explanation:

(4b^2+3)(4b^2-3)

since it is the expanded form of formula a^2-b^2=(a+b)(a-b) we can write,

=(4b^2)^2-(3)^3

=16b^4-9

8 0

2 years ago

The volume of a cone varies jointly with the area of the base and the height. When the area of the base is 27 cm2 and the height

Tomtit [17]

Cone=cup:
V=124cm^3.
h=12cm
V=Bh
P=r^2π+rsπ:
B=r^2π
B=V/h=124/12=10,3cm^2
r^2=B/π
r=√(B/π)=1,81 cm
S=√(r^2+h^2)=√(12^2+1.81^2)=√(144+3,28)=12,13 cm
P=r^2π+rSπ=3,28*3,14+1,81*12,13*3,14=10,29+68,93=79,22 cm^2

3 0

3 years ago

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vichka [17]

Answer:

4 $\sqrt{3}$