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stiv31 [10]
3 years ago
14

The bending of light as it passes into a transparent material of different optical intensity is known as

Physics
1 answer:
Tom [10]3 years ago
6 0
The bending of light as it passes into a transparent material of different optical intensity is known as refraction. The correct option among all the options given in the question is option "C".It can never be reflection as reflection is the bouncing of the light from a surface and so option “A” can easily be negated. The last option or option “D”<span> conversion and it mean converting something to another and that means a total change of form. So the last option should also be negated. The second option can also be negated.</span>
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I think the correct answer is C
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3 years ago
An electric motor spins at 1000 rpm and is slowing down at a rate of 10 t rad/s2 ; where t is measured in seconds. (a) If the mo
REY [17]

Answer:

a) The tangential component of acceleration at the edge of the motor at  t = 1.5\,s is -1.075 meters per square second.

b) The electric motor will take approximately 3.963 seconds to decrease its angular velocity by 75 %.

Explanation:

The angular aceleration of the electric motor (\alpha), measured in radians per square second, as a function of time (t), measured in seconds, is determined by the following formula:

\alpha = -10\cdot t\,\left[\frac{rad}{s^{2}} \right] (1)

The function for the angular velocity of the electric motor (\omega), measured in radians per second, is found by integration:

\omega = \omega_{o} - 5\cdot t^{2}\,\left[\frac{rad}{s} \right] (2)

Where \omega_{o} is the initial angular velocity, measured in radians per second.

a) The tangential component of aceleration (a_{t}), measured in meters per square second, is defined by the following formula:

a_{t} = R\cdot \alpha (3)

Where R is the radius of the electric motor, measured in meters.

If we know that R = 7.165\times 10^{-2}\,m, \alpha = 10\cdot t and t = 1.5\,s, then the tangential component of the acceleration at the edge of the motor is:

a_{t} = (7.165\times 10^{-2}\,m)\cdot (-10)\cdot (1.5\,s)

a_{t} = -1.075\, \frac{m}{s^{2}}

The tangential component of acceleration at the edge of the motor at  t = 1.5\,s is -1.075 meters per square second.

b) If we know that \omega_{o} = 104.720\,\frac{rad}{s} and \omega = 26.180\,\frac{rad}{s}, then the time needed is:

26.180\,\frac{rad}{s} = 104.720\,\frac{rad}{s}-5\cdot t^{2}

5\cdot t^{2} = 104.720\,\frac{rad}{s}-26.180\,\frac{rad}{s}

t^{2} = \frac{104.720\,\frac{rad}{s}-26.180\,\frac{rad}{s}  }{5}

t = \sqrt{\frac{104.720\,\frac{rad}{s}-26.180\,\frac{rad}{s}  }{5} }

t \approx 3.963\,s

The electric motor will take approximately 3.963 seconds to decrease its angular velocity by 75 %.

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Answer:

I think acute stress is short term, episodic is stress that happens in a pattern but more frequent and chronic stress is a diagnosed stress that is long term

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Two oppositely charged particles are attracted to each other with a force of 2.7 newtons. What the new force be if only one of t
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As pitch gets higher, wavelength gets ___________.
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Shorter

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Waves become shorter and closer together as pitch increases

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