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ss7ja [257]
3 years ago
9

Two oppositely charged particles are attracted to each other with a force of 2.7 newtons. What the new force be if only one of t

he charges is doubled?
Physics
2 answers:
maria [59]3 years ago
7 0
The charge will be positive
jekas [21]3 years ago
7 0

The complete equation is as follows:


Force between two charge particles = k * Q1 * Q2 / r^2,

where k is constant, Q1 is charge on 1 particle, Q2 is charge on the other particle and r is the distance between the particles.


From the equation, if one of the charges is doubled, then the force will also be doubled. It will become 7.6*2 = 15.2 Newtons.

You might be interested in
In an electric motor _____energy is transformed into_____energy?
irina1246 [14]

Answer:

mechanical energy

Explanation:

In an electric motor the electrical energy is converted into mechanical energy. Almost every mechanical movement that we see around us is accomplished by an electric motor. Electric machines are a means of converting energy. Motors take electrical energy and produce mechanical energy.

3 0
3 years ago
A 3.0 m tall, 40 cm diameter concrete column supports a 235,000 kg load. by how much is the column compressed? assume young's mo
statuscvo [17]
The Young modulus E is given by:
E= \frac{F L_0}{A \Delta L}
where 
F is the force applied
A is the cross-sectional area perpendicular to the force applied
L_0 is the initial length of the object
\Delta L is the increase (or decrease) in length of the object.

In our problem, L_0 = 3.0 m is the initial length of the column, E=3.0 \cdot 10^{10}N/m^2 is the Young modulus. We can find the cross-sectional area by using the diameter of the column. In fact, its radius is:
r= \frac{d}{2}= \frac{40 cm}{2}=20 cm=0.2 m
and the cross-sectional area is
A=\pi r^2 = \pi (0.20 m)^2=0.126 m^2
The force applied to the column is the weight of the load:
W=mg=(235000 kg)(9.81 m/s^2)=2.305 \cdot 10^6 N

Now we have everything to calculate the compression of the column:
\Delta L =  \frac{F L_0}{EA}= \frac{(2.305\cdot 10^6 N)(3.0 m)}{(3.0\cdot 10^{10}N/m^2)(0.126 m^2)} =1.83\cdot 10^{-3}m
So, the column compresses by 1.83 millimeters.
3 0
3 years ago
Read 2 more answers
A woman stands on a bathroom scale in a motionless elevator. When the elevator begins to move, the scale briefly reads only 0.64
Galina-37 [17]

Answer:

The downwards acceleration is 3.53 m/s2.

Explanation:

Let the true weight is m g.

The reading of the balance, R = 0.64 mg

Let the acceleration is a.

As the apparent weight is less than the true weight so the elevator goes down wards with some acceleration.

Use Newton's second law

m g - R = m a

m g - 0.64 m g = m a

0.36 g = a

a = 3.53 m/s2

6 0
3 years ago
Calculate the speed of a proton after it accelerates from rest through a potential difference of 380 v .
nikitadnepr [17]

The magnitude of the change in potential energy is equal to the kinetic energy,

\left | \Delta U \right |= K

or                        

qV=\frac{1}{2} mv^{2}    

Here, V is potential difference, q is charge, m is mass and v is velocity.

We can also write,

v=\sqrt{\frac{2qV}{m} }

Given  V=380 V

Substituting this value with mass of proton, m=1.672\times10^{-27}  kg and charge of proton,q= 1.6\times10^{-19} C we get

v=\sqrt{\frac{2\times1.6\times10^{-19}C \times 380V}{1.672\times10^{-27}  kg} }\\\\v= 727.27\times10^{8} m/s =7.27\times10^{6}m/s

Therefore, the speed of proton is 7.27\times10^{6}m/s.


7 0
3 years ago
Read 2 more answers
During a circus act, a performer thrills the crowd by catching a cannon ball shot at him. The cannon ball has a mass of m1 = 7.5
vladimir1956 [14]

Answer:

Explanation:

We shall apply law of conservation of momentum .

total Initial momentum =

7.5 x 8.85 = 66.375 kg m / s

total mass = 7.5 + 61.5 = 69 kg , common velocity of ball and performer be v

Total momentum = 69 v

69 v  = 66.375

v = 66.375 / 69

= .962 m /s .

3 0
3 years ago
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