Answer:
The first one, since that is the only one showing in the screen,
and that is actually correct, since there are no intersecting points.
Step-by-step explanation:
Let the height above which the ball is released be H
This problem can be tackled using geometric progression.
The nth term of a Geometric progression is given by the above, where n is the term index, a is the first term and the sum for such a progression up to the Nth term is
To find the total distance travel one has to sum over up to n=3. But there is little subtle point here. For the first bounce ( n=1 ), the ball has only travel H and not 2H. For subsequent bounces ( n=2,3,4,5...... ), the distance travel is 2×(3/4)n×H
a=2H..........r=3/4
However we have to subtract H because up to the first bounce, the ball only travel H instead of 2H
Therefore the total distance travel up to the Nth bounce is
For N=3 one obtains
D=3.625H
Answer:
1. 3.5 units up
2. 3/4 units down.
3. down 3 units
4. up 2 units, right 1
5. up 4 units, right 3
6. down 4 units, left 2
Step-by-step explanation:
We are given equation g = 748u, where g is the total number of gallons of water used and u is the number of units.
We can see that the number of units of water being used by customers.
The number of units of water doesn't depend on the total number of gallons of water used.
Therefore, the number of units u is an independent variable.
The value of the total number of gallons is totally depends on the number of units used.
Therefore, the total number of gallons of water used g is a dependent variable.
So, we can conclude following statements:
1) g is the dependent variable.
2) u is the independent variable.
Answer:
1) Place the compass point at the vertex of the angle and open it to any width. Draw an arc that intersects of the sides of the angle.
2) Place the compass point at the one of the intersection points. Place the pencil at the other intersection point. This sets the compass with.
3) Draw an arc inside the angle.
4) Move the compass point to the intersection point on the other side of the angle being sure to keep the compass width the same. Draw a second arc inside the angle.
5) Make a point where the 2 arcs intersect the angle. Use a straight edge to draw a ray from the vertex of the angle through the point.
