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Yuri [45]
3 years ago
7

Kathleen had a bag of candy-coated chocolates. Of the 60 candies in the bag, 20% were red, 30% were orange, 30% were green, and

20% were blue. Of the blue ones, 10% had a damaged candy coating. Approximately how many of the blue ones had a damaged candy coating?
Mathematics
1 answer:
adelina 88 [10]3 years ago
8 0
1.2 of the blue candies were damaged. Out of the 60 candies, 18 were orange (0.3 x 60) and 18 were green (0.3 x 60). 12 of the candies were red (0.2 x 60) and 12 were blue (0.2 x 60). 1.2 of these 12 blue candies were damaged (0.1 x 12).
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Jennie has 7 tickets for carnival rides. The Ferris wheel costs 4 tickets, The roller coaster costs 6 tickets. the merry-go-roun
algol13

Answer: 6

Step-by-step explanation:

7 - 3 = 4

3 - 4 = 0

0 - 6 = -6

6 0
3 years ago
Simplify the expression using the order of operations (12-8)^3-2*7+√36
mestny [16]

Pull terms out from under the radical, assuming positive real numbers.

56

Have a good one :)

7 0
3 years ago
I WILL GIVE BRANIST plz help me
Natalija [7]

Answer:

10/8

Step-by-step explanation:

What you should do is awfully simple. Multiply 2 by 5 and put the product over 8.

(2 * 5)/8

10/8

The problem does say to leave my answer as an improper fraction, so 10/8 is the final answer.

7 0
3 years ago
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Maurinko [17]

Answer:

Step-by-step explanation:

Part time workers  daily rate = x.

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4 0
3 years ago
i already have the answers but i need to show my work. ill tell you my insta and please show me a picture of the work :))
Elodia [21]

Answer:

1:

{( - 6)}^{2}  \times  {( - 6)}^{5}

from law of indices:

{a}^{n}  \times  {a}^{m}  =  {a}^{(n + m)}

therefore:

= ( - 6) {}^{ \{2 + 5 \}}  \\  = ( - 6) {}^{7}  \\  = { \boxed{ \boxed{ - 279936}}}

2:

- 4 {a}^{5} (6 {a}^{5} ) \\  = ( - 4 \times 6)( {a}^{5}  \times  {a}^{5} ) \\  =  - 24  \{{a}^{(5 + 5)}  \} \\  = { \boxed{ \boxed{ - 24 {a}^{10} }}}

3:

( - 7 {a}^{4} b {c}^{3} )(5a {b}^{4}  {c}^{2} ) \\  = ( - 7 \times 5)( {a}^{4}  \times a)(b \times  {b}^{4})  \times ( {c}^{3}  \times  {c}^{2} ) \\  =  - 35 {a}^{5}  {b}^{5 }  {c}^{5}  \\  = { \boxed{ \boxed{ - 35 {(abc)}^{5} }}}

4:

\frac{ {8}^{15} }{ {8}^{13} }

from law of indices:

\frac{a {}^{n} }{ {a}^{m} }  =  {a}^{(n - m) }  \\

therefore:

=  {8}^{(15 - 13)} \\ { \boxed{ \boxed{ {8}^{2} = 64 }}}

follow the procedure for application to other questions.

<em>Any</em><em> </em><em>question</em><em>,</em><em> </em><em>be</em><em> </em><em>free</em><em> </em><em>to</em><em> </em><em>ask</em><em>.</em><em> </em>Thank you …

6 0
3 years ago
Read 2 more answers
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