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elena-14-01-66 [18.8K]
3 years ago
12

Consider two slides, both of the same height. One is long and the other is short. From which slide will a child have a greater f

inal speed when sliding off? Assume that there is no friction acting.
Physics
1 answer:
Lunna [17]3 years ago
8 0

Answer:

The final speed will be the same for the children on the shorter side and on the longer side.

Explanation:

This is because since the they are the same distance above the ground, their potential energy which is a function of mass, acceleration due to gravity and vertical height are the same.

PE = Mass × gravity × vertical height

At this point, we can deduce that the horizontal length of the slide has no effect on the potential energy. Only the vertical height does.

All this potential energy is converted to kinetic energy at the end of the slide. Since the potential energy is the same, then the kinetic energy will be the same and thus their velocity is the same.

Mathematically, consider that PE = mgh and KE = \frac{1}{2}mv^{2}

at the bottom of the slide, since energy has to be conserved, PE must be equal to KE.

mgh = \frac{1}{2}mv^{2}

final velocity of the child , v = \sqrt{2gh}

It shows the final velocity is only a function f acceleration due to gravity and height.

Thus, making their velocities equal.

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Muscular strength is defined as the maximum amount of force that a muscle can exert against some form of resistance in a single effort. ... In the gym, a single repetition at a given weight is an example of muscular strength.

Explanation:

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What is true about an iceberg and the water surrounding the iceberg?
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The answer is D statement "Their temperatures are not the same but you can't tell which is greater without a thermometer". The iceberg can move through the ocean and passed through a various temperature of the ocean. The ocean stays at the same temperature whether it's lower or higher than the iceberg's temperature because of the salt.
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The earth exerts a gravitational force of 850N on John. What is Johns mass in kg
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Answer:

86.73 kg

Explanation:

Remember that F=mg

Let's plugin our numbers

850N=m9.8m/s^2

850N=9.8m/s^2m

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2 years ago
An open 1-m-diameter tank contains water at a depth of 0.7 m when at rest. As the tank is rotated about its vertical axis the ce
Mamont248 [21]

Answer:

Explanation:

To find the angular velocity of the tank at which the bottom of the tank is exposed

From the information given:

At rest, the initial volume of the tank is:

V_i = \pi R^2 h_i --- (1)

where;

height h which is the height for the free surface in a rotating tank is expressed as:

h = \dfrac{\omega^2 r^2}{2g} + C

at the bottom surface of the tank;

r = 0, h = 0

∴

h = \dfrac{\omega^2 r^2}{2g} + C

0 = 0 + C

C = 0

Thus; the free surface height in a rotating tank is:

h=\dfrac{\omega^2 r^2}{2g} --- (2)

Now; the volume of the water when the tank is rotating is:

dV = 2π × r × h × dr

Taking the integral on both sides;

\int \limits ^{V_f}_{0} \ dV = \int \limits ^R_0 \times 2 \pi \times r \times h \ dr

replacing the value of h in equation (2); we have:

V_f} = \int \limits ^R_0 \times 2 \pi \times r \times ( \dfrac{\omega ^2 r^2}{2g} ) \ dr

V_f = \dfrac{ \pi \omega ^2}{g} \int \limits ^R_0 \ r^3 \ dr

V_f = \dfrac{ \pi \omega ^2}{g} \Big [  \dfrac{r^4}{4} \Big]^R_0

V_f = \dfrac{ \pi \omega ^2}{g} \Big [  \dfrac{R^4}{4} \Big] --- (3)

Since the volume of the water when it is at rest and when the angular speed rotates at an angular speed is equal.

Then V_f  =  V_i

Replacing equation (1) and (3)

\dfrac{\pi \omega^2}{g}( \dfrac{R^4}{4}) = \pi R^2 h_i

\omega^2 = \dfrac{4g \times h_i }{R^2}

\omega =\sqrt{ \dfrac{4g \times h_i }{R^2}}

\omega = \sqrt{\dfrac{4 \times 9.81 \ m/s^2 \times 0.7 \ m}{(0.5)^2} }

\omega = \sqrt{109.87 }

\mathbf{\omega = 10.48 \ rad/s}

Finally, the angular velocity of the tank at which the bottom of the tank is exposed  = 10.48 rad/s

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3 years ago
What is a permanent magnet​
Wewaii [24]

Answer:

a magnet that retains its magnetic properties in the absence of an inducing field or current

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