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KATRIN_1 [288]
3 years ago
13

How much work is required to stop an electron (m = 9.11 \times 10^ - 31 kg) which is moving with a speed of 2.10

Physics
1 answer:
Karo-lina-s [1.5K]3 years ago
6 0

Answer:

-2.00876\times 10^{-18}\ J

Explanation:

v = Speed of electron = 2.1\times 10^6\ m/s (generally the order of magnitude is 6)

m = Mass of electron = 9.11\times 10^{-31}\ kg

Work done would be done by

W=K_i-K_f\\\Rightarrow W=0-\dfrac{1}{2}mv^2\\\Rightarrow W=0-\dfrac{1}{2}\times 9.11\times 10^{-31}\times (2.1\times 10^6)^2\\\Rightarrow W=-2.00876\times 10^{-18}\ J

The work required to stop the electron is -2.00876\times 10^{-18}\ J

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2 years ago
group of students is making model cars that will be propelled by model rocket engines. These engines provide a nearly constant t
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Answer:

increase.

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F = m a

If the force acting is constant, then.

m∝ \frac{1}{a}

That is if the mass of object increases the acceleration decreases and vice versa. The above equation is used when the force acting on the body is constant.

As the thrust force from the rocket engine is constant throughout there will be a variation in the mass or acceleration.

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3 years ago
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Answer:

The vehicle with the most mass

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