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o-na [289]
3 years ago
13

What is the difference between an incendiary fire and an accidental fire

Chemistry
1 answer:
vampirchik [111]3 years ago
6 0

Answer:

An incendiary fire is when a fire is intentionally started knowing it shouldn't be. And an accidental fire is when a fire is started accidentally or without purposeful intent.

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Low energy waves have (3 points)
Sergeeva-Olga [200]

Answer:

Low energy waves have <u>a long wavelength.</u>

Explanation:

Energy of wave is directly related to  the frequency while it is inversely proportional to the wavelength.

If any wave have high energy it will have high frequency and smaller wavelength.

If the wave have lower energy then it will have lower frequency and higher wavelength.

Mathematical relationship:

E = h. f

E = h. c/λ

E= energy

h = planck's constant

f = frequency

c = speed of light

λ = wavelength

7 0
3 years ago
How many joules it take to melt 35g of ice at 0
tekilochka [14]
We can't even see half of the question
8 0
3 years ago
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An atom of the element iron has an atomic number of 26 and an atomic weight of 56. if it is neutral, how many protons, neutrons,
guapka [62]
Proton 26
neutron 0
you can tell how many proton by the atomic number
3 0
3 years ago
The absorbance of an equilibrium mixture containing FeSCN2 was measured at 447 nm and found to be 0.347. What is the equilibrium
Ksenya-84 [330]

Answer:

The concentration is C = 1.11 mol/L

Explanation:

From the question we are told that

     The absorbance is  A = 0.347

       The length is  l =  447 nm  =  447 *10^{-7} \ cm

     

Generally absorbance is mathematically represented as

        A =  \epsilon*  C * l

where \epsilon is the molar absorptivity of  FeSCN2  with a value \epsilon  =  7.0*10^3 L/cm/mol

 and  C is the equilibrium concentration of FeSCN2

So  

       C = \frac{A}{\epsilon *  l  }

substituting values

        C = \frac{0.347}{7.0*10^{3} *  447 *10^{-7}  }

         C = 1.11 mol/L

5 0
2 years ago
A change in which property of light will have no effect on whether or not the photoelectric effect occurs??? Frequently energy i
slavikrds [6]
Intensity has no affect on whether or not the photoelectric effect occurs.  The determining property is frequency and since frequency and wavelength are inversely proportional, wavelength matters as well.  If a frequency of light can't cause the photoelectric effect to happen, no matter what the intensity is, the light can't make it happen.

I hope this helps.  Let me know in the comments if anything is unclear.
5 0
3 years ago
Read 2 more answers
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