2 years ago

¿Cuáles son las características de los materiales de laboratorio? Por ejemplo: exactitud, resistencia a la temperatura, etc.

Chemistry

2 answers:

ira [324]2 years ago

6 0

No se perdón que no pueda ayudar:(

irina [24]2 years ago

4 0

Answer:

gfchjklnmbvh

Explanation:

You might be interested in

Explain how changes in temperature affect the particle motion of a substance.

Travka [436]

When the temperature increases, warms, or heats up the molecules become excited. Their movement becomes faster and they tend to move far apart from other molecules.

8 0

3 years ago

The reaction between nitrogen dioxide and carbon monoxide is NO2(g)+CO(g)→NO(g)+CO2(g)NO2(g)+CO(g)→NO(g)+CO2(g) The rate constan

Alex17521 [72]

Answer : The rate constant at 525 K is, $0.0606M^{-1}s^{-1}$

Explanation :

According to the Arrhenius equation,

$K=A\times e^{\frac{-Ea}{RT}}$

or,

$\log (\frac{K_2}{K_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}]$

where,

$K_1$ = rate constant at $701K$ = $2.57M^{-1}s^{-1}$

$K_2$ = rate constant at $525K$ = ?

$Ea$ = activation energy for the reaction = $1.5\times 10^2kJ/mol=1.5\times 10^5J/mol$

R = gas constant = 8.314 J/mole.K

$T_1$ = initial temperature = 701 K

$T_2$ = final temperature = 525 K

Now put all the given values in this formula, we get:

$\log (\frac{K_2}{2.57M^{-1}s^{-1}})=\frac{1.5\times 10^5J/mol}{2.303\times 8.314J/mole.K}[\frac{1}{701K}-\frac{1}{525K}]$

$K_2=0.0606M^{-1}s^{-1}$

Therefore, the rate constant at 525 K is, $0.0606M^{-1}s^{-1}$

8 0

3 years ago

Which of the following is a product of photosynthesis reaction

SpyIntel [72]

Glucose and Oxygen
Hope this helped you out

5 0

3 years ago

Read 2 more answers

Question 5

Zina [86]

Answer:

Explanation:

2.2 g/mL is the answer.

4 0

2 years ago

I need help asap please

monitta

unbalanced

there has to be 4 hydrogens in total on both sides

4 0

3 years ago