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2 years ago

If you wanted to neutralize 4.00g NaOH, what volume of 1.0 M HCl would you need ?

1 answer:

4 0

This is a simple acid base reaction.
To neutralize all NaOH, the moles in 4.00g of NaOH should be equal to the moles of HCl since the stoichiometric ratio between NaOH and HCl is 1 : 1.

NaOH + HCl → NaCl + H₂O

Molar mass of NaOH = (23 + 16 + 1 ) g mol⁻¹
Moles in NaOH = mass / molar mass = 4.00 g / 40 g mol⁻¹ = 0.1 mol
HCl moles = 0.1 mol

concentration = number of moles (mol) / volume (L)

Hence HCl volume = 1.0 mol/L x 0.1 mol = 0.1 L = 100.0 mL

To neutralize 4.00 g of NaOH, 100.0 mL of 1.0 M HCl is needed.

You might be interested in

The mole fraction of hcl in a solution prepared by dissolving 5.5 g of hcl in 200 g of c2h6o is ________. the density of the sol

Thepotemich [5.8K]

The answer:
all that we search for is the number of mole of HCl and the number of mole of C2H6O

M(HCl) = 5.5g/ mole of HCl , so mole of HCl = 5.5/M(HCl), where M(HCl) is the molar mass.
M(HCl) = 1+ 36.5= 37.5

moles of HCl = 5.5/37.5=0.14

M(C2H6O) = 200g / moles of C2H6O, so moles of C2H6O=200g / M(C2H6O)

M(C2H6O)= 2x12+ 6 + 16=46,

moles of C2H6O=200g / 46 =<span>4.35 </span><span> moles
</span>
the sum of the moles is 0.14 + <span>4.35 </span> = 4.501 moles

finally, <span>The mole fraction of hcl in a solution prepared by dissolving 5.5 g of hcl in 200 g of c2h6o is 0.031
</span>
because it can be found by 0.14 / 4.501= 0.031

5 0

3 years ago

Analyses of enzymes found in the blood are used as indicators that tissue damage (heart, liver, muscle) has occurred and resulte

Reika [66]

Answer:

True.

Explanation:

Yes, analyses of enzymes found in the blood are used as indicators of tissue damage in the heart, liver, muscle etc has occurred. This leakage of enzymes into the bloodstream tells us whether the tissue is damaged or not. Lactate dehydrogenase is a type of enzyme which is used as indicator which is responsible for the interconverts lactate and pyruvate. The concentration of this enzyme in the blood tells us about tissue damage.

7 0

3 years ago

Read 2 more answers

An element is a pure substance in which there are how many kinds of atoms?

Ostrovityanka [42]

Answer:

One

Explanation:

An element is a pure substance in which there are only one kind of atom. Elements are distinct substances that cannot be split up into simpler substances.

Such substances consists of only one kind of atom. There are over a hundred known elements to date.

Generally, as a pure substance, the composition of an element is definite and they are homogenous in all parts.

8 0

2 years ago

If we mix 25 grans if sodium oxide with a large amount of potassium chloride, how many grams of sodium chloride should be produc

amid [387]

Answer:

47.2 g

Explanation:

Data given:

mass of Sodium oxide (Na₂O) = 25 grams

mass of potassium chloride (KCl) = excess

amount of sodium chloride (NaCl) = ?

Solution:

First we look for reaction of sodium oxide with potassium chloride.

Na₂O + 2 KCl -----------> 2 NaCl + K₂O

As we know that potassium chloride is in excess amount and sodium oxide is 25 g so it means sodium oxide is a limiting reactant and amount of sodium chloride depends on the amount of sodium oxide.

So, now we will look for mole mole ration of Na₂O to NaCl.

Na₂O + 2 KCl -----------> 2 NaCl + K₂O

1 mol 2 mol

from above equation we come to know that 1 mole of Na₂O gives 2 moles of NaCl.

Now convert moles to mass

As we Know

Molar mass of Na₂O = 2(23) + 16 = 62 g/mol

Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol

Na₂O + 2 KCl -----------> 2 NaCl + K₂O

1 mol (62 g/mol) 2 mol (58.5 g/mol)

62 g 117 g

So, it means that 62 g of Na₂O produce 117 g of NaCl then how many grams of NaCl will be produce by 25 g of Na₂O

Apply unity formula

62 g of Na₂O ≅ 117 g of NaCl

25 g of Na₂O ≅ X g of NaCl

Do cross multiplication

X g of NaCl = 117 g x 25 g / 62 g

X g of NaCl = 47.2 g

So,

25 g of Na₂O gives 47.2 grams of NaCl.

4 0

3 years ago

1.5 moles of Al is how many<br> atoms?

aev [14]

Answer:

<h2>9.03 × 10²³ atoms </h2>

Explanation:

The number of atoms of Al can be found by using the formula

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

N = 1.5 × 6.02 × 10²³

We have the final answer as

<h3>9.03 × 10²³ atoms</h3>

Hope this helps you

4 0

2 years ago