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gulaghasi [49]
3 years ago
5

If you wanted to neutralize 4.00g NaOH, what volume of 1.0 M HCl would you need ?

Chemistry
1 answer:
iragen [17]3 years ago
4 0
This is a simple acid base reaction.
To neutralize all NaOH, the moles in 4.00g of NaOH should be equal to the moles of HCl since the stoichiometric ratio between NaOH and HCl is 1 : 1.

NaOH + HCl → NaCl + H₂O

Molar mass of NaOH = (23 + 16 + 1 ) g mol⁻¹
Moles in NaOH = mass / molar mass = 4.00 g / 40 g mol⁻¹ = 0.1 mol
HCl moles = 0.1 mol

concentration = number of moles (mol) / volume (L)

Hence HCl volume = 1.0 mol/L x 0.1 mol = 0.1 L = 100.0 mL

To neutralize 4.00 g of NaOH, 100.0 mL of 1.0 M HCl is needed.
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How much time is needed to deposit 1.0 g of chromium metal from an aqueous solution of crcl3 using a current of 1.5 a?
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The metal component of the given compound, CrCl3, is chromium. The number of moles per 1 g of chromium is calculated through the equation below,

        n = (1 g Cr)(1 mol Cr/51.996 g Cr)
              n = 0.0192 mol Cr(3 electrons/1 mol Cr) 
                n = 0.0577 e-

Determine the number in charge by multiplying with Faraday's constant,

      C = (0.0577 mol Cr)((1 F/1 mol e-)(96485 C/ 1F)
             C = 5,566.87 C

Then, calculate time by dividing the charge with the current,

     t = 5566.87 C/1.5 A 
     t = 3711.25 minutes
     t = 61.84 hours

<span><em>Answer: 61.84 hours</em></span>


8 0
3 years ago
Read 2 more answers
2 gallons is equal to how many liters
Arte-miy333 [17]

Answer:

7.57082

Explanation:

its just the answer

7 0
3 years ago
what pressure must be applied to compress a gas from 85 L at 3.5 atm to 15 L? a-17.3atm b-24.7atm c-19.8atm d-21.4atm
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A... I think ., not sure
5 0
3 years ago
LICUICY NICULUM
Evgen [1.6K]

Answer:

Missing component

Cl₂

H₂O

Explanation:

Reaction given:

? + 2NaBr → 2NaCl+Br

Mg+? → MgO+H2

missing component = ?

Solution:

Reaction 1

             ? + 2NaBr -----→ 2NaCl + Br

if we look at the reactants and products there is one element is in product side but not shown in the reactant side.

In products there are following atoms

Na (Sodium)

Cl (Chlorine)

Br (Bromine)

In Reactant there are following atoms

Na (Sodium)

Br (Bromine)

So only Chlorine is missing in the reactant side.

if we put chlorine in the reactant then this reaction will be complete

        Cl + 2 NaBr -----→ 2NaCl + Br

So chlorine react with water and give sodium chloride and bromine molecule, this is a single displacement reaction and chlorine replace bromine in the above reaction

Now balance the equation

          Cl₂ + 2 NaBr -----→ 2NaCl + Br₂

So, the missing component is

  • Cl₂

____________

Reaction 2

                Mg + ? ---------→ MgO + H₂

if we look at the reactants and products there are two element in product side but not shown in the reactant side.

In products there are following atoms

Mg (Magnesium)

O (Oxygen)

H (Hydrogen)

In Reactant there is only one following atom

Mg (Magnesium)

So Oxygen and Hydrogen is missing in the reactant side.

if we put water molecule (H₂O) in the reactant then this reaction will be complete

          Mg + H₂O ---------→ MgO + H₂

in this reaction magnesium (Mg) react with water (H₂O) and give magnesium oxide and hydrogen gas.

So, the missing component is

  • H₂O

3 0
3 years ago
Read 2 more answers
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