Parallel-plate capacitor has there fore formula is
<span>C=(<span>ϵ0</span>A)/d
putting values</span>C=(8.85*10^-12*pi*.05^2)/.00063
=1.1*10^-10F
then Q=CV=1.1*10^-10*1000=1.1*10^-7C
as
<span>η=Q/A</span><span>therefore
(1.1*10^-7)/(pi*.05^2)
=1.4*10^-5C/m^ our answer
hope this helps</span>
Answer: Elastic Potential Energy
Explanation: Energy present on compressed strings is called Elastic Potential Energy.
<h2>Answer </h2>
<h3>1) iron </h3>
<h3>2) Aluminium </h3>
<h3>3) sliver </h3>
<h3>4) copper </h3>
I hope it's helpful for you ☺️
Answer:
Explanation:
radius of gyration of wheel k then
k² = r²/2
r² = 2 k²
r = √2 k
= 1.414 x .3 m
r = .4242 m
Moment of inertia of wheel
= mass x radius of gyration ²
= 25 x .3 x .3
= 2.25 kg m²
Friction force acting on it ( sliding )
= μmg , μ being coefficient of kinetic friction
This friction force will create linear acceleration in forward direction
Acceleration produced
= μg
= .6 x 9.8
= 5.88 m / s ²
This will also rotate the wheel , angular acceleration being
linear acceleration / radius
= 5.88 /.4242
= 13.86 radian / s²
Maintaining an orbit has nothing to do with the satellite's speed.
ANY (tangential) speed is enough to stay in orbit, if the satellite
just stays away from Earth's atmosphere.
If the satellite completely stops moving 'sideways' at all, and just
hangs there, then the forces of gravity between the satellite and
the Earth will pull them together ... the satellite will fall into the
atmosphere and then to the ground.
