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3 years ago

The binding energy of a nucleus can be found using

Physics

2 answers:

Svet_ta [14]3 years ago

8 0

Answer:

converting that mass to energy by using E=mc2. Mass must be in units of kg. Once this energy, which is a quantity of joules for one nucleus, is known, it can be scaled into per-nucleon and per-mole quantities.

Explanation:

Yuri [45]3 years ago

5 0

Answer:

An elephants balls

Explanation:

You might be interested in

Which of the following does not describe elements?

Eddi Din [679]

They cannot be separated by a chemical reaction. There's nothing to separate them into.

If my answer is correct, please set it as the brainliest answer for others to see.

7 0

4 years ago

An inquisitive physics student and mountian climber climbs a 47.2 m cliff that overhangs a calm pool of water. He throws two sto

elena-s [515]

Answer:

The two stoned hit the water after 2.92s after the first stone satat to drop

Explanation:

We have this data:

x = distance = 47.2m

So = initial speed = 1.8m/s

A = In this case is equal to gravity = 9.8 m/s2

First we are going to calculate the final speed, We are going to use this equation

$Sf^2= So^2 + (2*a*x)$

Where Sf= final speed

We put the data

$Sf^2= 928.36m^{2}/s^{2}$

We need to calculate the square root

$Sf= 30.47m/s$

The final speed is 30.47m/s

The next steep is calculate the time that the first stone spend during its drop.

We are going to use the next equation

$t=\frac{Sf-So}{a}$

We put tha data

$t=\frac{30.47m/s-1.8m/s}{9.8m/s^{2} }$

$t= 2.92s$

We do not use 0.8s because we calculate all the things with the first stone, This stone spend more time that the second stone

3 0

4 years ago

A pipe of length 2.7 m is closed at one end and sustains a standing wave at its second overtone. Determine the distance between

Morgarella [4.7K]

The distance between an antinode and adjacent node is 0.54m

<u>Explanation:</u>

Given:

Length of the pipe, L = 2.7m

Pipe is closed at one end

Standing wave is at 2nd overtone

Distance between a node and adjacent antinode, d = ?

In a pipe, closed at one end and open at one end, the 1st overtone is the 3rd harmonic( n=3 ) and 2nd overtone is the 5th harmonic(n=5).

Antinodes and nodes are always formed equidistant.

So, the distance between an antinode and node would be one-fifth of the length of the pipe.

So, the distance would be $\frac{L}{5}$ ( n = 5)

$d = \frac{2.7}{5} \\\\d = 0.54m$

Thus, the distance between an antinode and adjacent node is 0.54m

3 0

3 years ago

Rank the following five quantities in order from the largest to the smallest. If two of the quantities are equal, give them equa

Sedaia [141]

Answer:

Explanation:

In this case, we need to rank the following quantities in order from the largest to the smallest. The quantities are as follows :

(a) 0.031 kg (b) 6 g (c) 1.5 105 mg (d) 4.6 10-8 Gg (e) 1.5 108 µg

Firstly, it is required to convert all the units in one single unit so as to rank the given quantities. Let's convert all the quantities in grams (g).

(a) 0.031 kg = 31 g

(b) 6 g