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givi [52]
3 years ago
9

A charge of -2.720 μC is located at (3.000 m , 4.591 m ), and a charge of 1.600 μC is located at (-2.626 m , 0).There is one poi

nt on the line connecting these two charges where the potential is zero. Find this point. There is one point on the line connecting these two charges where the potential is zero. Find this point. Express your answers using three decimal places separated by a comma.
x,y = ______ m please help!
Physics
1 answer:
Alexxandr [17]3 years ago
8 0

Answer:

Explanation:

Given that,

Q1=-2.72μC

At the position r1 =(3 , 4.591)m

Q2=1.600 μC

Located at (-2.626 m , 0)

Let the point where the electric potential will be zero be (x, y)

Therefore,

r1=(3-x, 4.952-y)

r2=(-2.626-x, -y)

Then, electric potential at that point is given as

V1+V2=0

Then,

KQ1/r1 +KQ2/r2=0

Divide through by k

Q1/r1+Q2/r2=0

-2.72/(3-x, 4.952-y) + 1.6/(-2.626-x, -y)=0

2.72/(3-x, 4.952-y) =1.6/(-2.626-x, -y)

For x axis

2.72/(3-x)=1.6/(-2.626-x)

Cross multiply

2.72(-2.626-x)=1.6(3-x)

-7.14272-2.72x=4.8-1.6x

-2.72x+1.6x=4.8+7.14272

-1.12x=11.94272

x=-11.94272/1.12

x=-10.663m

For y axis

2.72/(3-x, 4.952-y) =1.6/(-2.626-x, -y)

2.72/(4.952-y)=1.6/-y

Cross multiply

-2.72y=1.6(4.952-y)

-2.72y=7.9232-1.6y

-2.72y+1.6y=7.9232

-1.12y=7.9232

y=7.9232/-1.12

y=-7.074m

(x, y)=(-10.663, -7.074)m

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Find the ratio of intensities in 4 different sets of red to violet spectral satellites in Raman scattering spectra of CCl4 molecules at T=27C temperature if corresponding resonant infrared frequencies (equivalent to frequencies of nuclei vibrations) of CCl4 molecule are 217, 315, 457 and 774 cm-1 . (Note: Wavenumber N in cm-1 is defined as N=1/\lambda\  cm^{-1})

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 From the question we are told that

        The number of sets of satellite is n = 4

        The temperature is  T = 27 ^oC

        The resonant infrared frequencies are f_1 = 217 cm^{-1}

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From the question we see that the wave number also has a unit ofcm^{-1} hence  the value of the wave numbers of the molecule are

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         N  = \frac{1}{\lambda }

Therefore

          I \ \ \alpha \ \  N

This implies that  the ratio of intensity in first set to that of second set to that of third set to that of fourth set is  equal to the ratio of the wavenumber in the first set to that of the second set  to that of third set to that of fourth

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