Look at the velocity versus time graph below. What is the magnitude of the displacement of the object after it travels for three
seconds?
A. 14 m
B. 10 m
C. 12 m
D. 16 m
A. 14 m
B. 10 m
C. 12 m
D. 16 m
1 answer:
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Answer:
The bike traveled 31.3 meters during this period
Explanation:
A speed bike tops a hill at 3.50 m/s and accelerates steadily down the
hill until reaching a speed of 11.4 m/s after 4.20 seconds
→ The initial speed u = 3.5 m/s
→ The final speed v = 11.4 m/s
→ The time of acceleration t = 4.2 seconds
→ a =
Substitute the values above in the rule to find the acceleration a
→ a = = 1.88 m/s²
We need to find the distance that the bike traveled during the
acceleration
→ v² = u² + 2 a s, where s is the distance
→ (11.4)² = (3.5)² + 2 (1.88)(s)
→ 129.96 = 12.25 + 3.76 s
Subtract 12.25 from both sides
→ 117.71 = 3.76 s
Divide both sides by 3.76
→ s = 31.3 meters
<em>The bike traveled 31.3 meters during this period</em>