First, assume the order of the given reaction is n, then the rate of reaction i.e. ![\frac{dx}{dt}=k\times[A]^{n}](https://tex.z-dn.net/?f=%5Cfrac%7Bdx%7D%7Bdt%7D%3Dk%5Ctimes%5BA%5D%5E%7Bn%7D)
where, dx is change in concentration of A in small time interval dt and k is rate constant.
According to units of rate constant, the reaction is of second order.
(second order formula)
Put the values,

t= 587.9 s
Hence, time taken is 587.9 s
Answer:
1.17 grams
Explanation:
Let's consider the balanced equation for the combustion of ethylene.
C₂H₄(g) + 3 O₂(g) → 2 CO₂(g) + 2 H₂O(l)
We can establish the following relations:
- 1411 kJ are released (-1411 kJ) when 1 mole of C₂H₄ burns.
- The molar mass of C₂H₄ is 28.05 g/mol.
The grams of C₂H₄ burned to give 59.0 kJ of heat (q = -59.0 kJ) is:

Answer:
92.26% of C
Explanation:
To solve this problem we must assume we have 1 mole of benzene. The mole contains 6 moles of C and 6 moles of H. We have to convert these moles to grams in order to find the total mass and mass percent will be:
Mass atom / Total mass * 100
<em>Mass C: </em>6mol C * (12.0107g / mol) = 72.0642g
<em>Mass H: </em>6mol H * (1.00794g / mol) = 6.04764g
<em>total mass: </em>72.0642g + 6.04764g = 78.11184g
Mass percent of C will be:
72.0642g C / 78.11184g* 100
<h3>92.26% of C</h3>
Valence (outermost) electrons. Chemical bonds are formed when an atom does not have a full outermost shell, i.e. there are 7 electrons and 1 more is needed, or there is only 1 electron, which can be transferred to another atom.
The circulatory system<span> also transports oxygen from the </span>lungs<span> to the cells. Now the cells have what they need for </span>cellular respiration<span>: oxygen and glucose. The teamwork doesn't end there, however. The </span>circulatory system<span> also transports carbon dioxide waste from the cells to the </span>lungs<span> of the </span>respiratory system<span>.</span>