How may moles are in 88.4 grams of Al(OH)3?

Select the correct answer from each drop-down menu.

Alika [10]

Answer:

Explanation:

There are three fundamentally known states of matter save for plasma and the Bose-Einstein condensate. These states of matter are solid, liquid and gas.

We can classify nearly all matter into these discrete categories based on certain lucid characteristics they exhibit.

Solids have definite shape and volume and they exhibit by the far the most remarkable internal ordering. Their molecules are attached by strong internal forces.
Liquids do not have a definite shape but takes the shape of the contains that hold them. They are not random and have internal cohesion among them.
Gases are random particles and highly varied. They move haphazardly and have no definite shape and volume.

4 0

3 years ago

Consider the reaction.

Alekssandra [29.7K]

Answer:The correct answer is option C.

Explanation:

$N_2(g)+3H_2(g)\rightarrow 2NH_3(g)$

At STP, 1 mol of gas occupies 22.4 L of volume

So, 100.0 L volume of $NH_3$ will be occupied by :

$\frac{1}{22.4 L}\times 100.0 L=4.4642 moles$

According to reaction 2 moles $NH_3$ are obtained from 1 mole of $N_2$ .

Then,4.4642 moles of $NH_3$ will be obtained from :

$\frac{1}{2}\times 4.4642$ that is 2.2321 moles of $N_2$

Mass of $N_2$ gas:

Moles of $N_2$ gas Molar mass of $N_2$ gas:

$2.2321 mol\times 28 g/mol=62.4988\approx 62.50 g$

Hence, the correct answer is option C.

4 0

3 years ago

Read 2 more answers

One solution has a formula C (n) H (2n) O (n) If this material weighs 288 grams, dissolves in weight 90 grams, the solution will

saw5 [17]

Explanation:

The given data is as follows.

Boiling point of water ( $T^{o}_{b}) = 100^{o}C$ = (100 + 273) K = 323 K,

Boiling point of solution ( $T_{b}) = 101.24^{o}C$ = (101.24 + 273) K = 374.24 K

Hence, change in temperature will be calculated as follows.

$\Delta T_{b} = (T_{b} - T^{o}_{b})$

= 374.24 K - 323 K

= 1.24 K

As molality is defined as the moles of solute present in kg of solvent.

Molality = $\frac{\text{weight of solute \times 1000}}{\text{molar mass of solute \times mass f solvent(g)}}$

Let molar mass of the solute is x grams.

Therefore, Molality = $\frac{\text{weight of solute \times 1000}}{\text{molar mass of solute \times mass f solvent(g)}}$

m = $\frac{288 g \times 1000}{x g \times 90}$

= $\frac{3200}{x}$

As, $\Delta T_{b} = k_{b} \times molality$

$1.24 = 0.512 ^{o}C/m \times \frac{3200}{x}$

x = $\frac{0.512 ^{o}C/m \times 3200}{1.24}$

= 1321.29 g

This means that the molar mass of the given compound is 1321.29 g.

It is given that molecular formula is $C_{n}H_{2n}O_{n}$ .

As, its empirical formula is $CH_{2}O$ and mass is 30 g/mol. Hence, calculate the value of n as follows.

n = $\frac{\text{Molecular mass}}{\text{Empirical mass}}$

= $\frac{1321.29 g}{30 g/mol}$

= 44 mol

Thus, we can conclude that the formula of given material is $C_{44}H_{88}O_{44}$ .

4 0

3 years ago

Ga3+ and Br1- is what formula?

Sladkaya [172]

$\text{GaBr}_3$

8 0

3 years ago

A metal(ii) ion solution of unknown concentration shows an absorbance of 0.55. what is the molar concentration of the metal (ii)

torisob [31]

Cover with metal .Any elements other than hydrozen and helium concentration shows an absorbance

4 0

3 years ago