Question

The specifications for an electronic device are 3.00 ± 0.10 amps. If the standard deviation is 0.02, what is the capability index? Write your answer to 2 decimal places (X.XX)

Answer 1

Answer:

The capability index of the device is 1.67.

Explanation:

It is given that,

The specifications for an electronic device are $(3\pm0.1)\ A$

Upper specification limit, $USL=3+0.1=3.1\ A$

Lower specification limit, $LSL=3-0.1=2.9\ A$

Standard deviation, $\sigma=0.02$

The capability index of an electronic device is given by :

$C_p=\dfrac{USL-LSL}{6\sigma}$

$C_p=\dfrac{3.1-2.9}{6\times 0.02}$

$C_p=1.666$

or

$C_p=1.67$

So, the capability index of the device is 1.67. Hence, this is the required solution.