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3 years ago

How do you factor x4-x3-7x2-x+6?

1 answer:

5 0

$x^4-x^3-7x^2-x+6=x^4-x^3-6x^2-x^2-x+6=\\ \\=x^2(x^2-x-6)-(x^2-x-6)=(x^2-1)(x^2-x-6)=\\ \\=(x-1)(x+1)(x^2-3x+2x-6)=\\ \\=(x-1)(x+1)[x(x-3)+2(x-3)]=(x-1)(x+1)(x-3)(x+2)$

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Chinedu sat down to do his homework, which included 30 math problems. He solved 2 problems each minute. Let f(n) be the number o

vova2212 [387]

Answer:

It would be an arithmetic sequence.

Step-by-step explanation:

This is because during each minute, he does another 2 problems. Or, in other words +2 each minute.

This is the result of the sequence during each minute:

(Problems Left): 30, 28, 26, 24, 22... 0

Time (Minutes) --->

If it was instead a geometric equation, it would go by a multiple, such as the number 2. Or, ×2 each minute.

During the first minute, he learns 2 problems. But then as each minutes passes it turns into 4, then 8, and etc..

This is the result of the pretend sequence during each minute: (Problems Left): 30, 28, 24, 16, 0

Time (Minutes) --->

The formula would be for this equation would follow

an = a1 + (n-1)d

an is your result.

a1 is the first number you plug in

(n-1) is just there, don't mind it (aka: the term position).

and d is the rate.

So just plug them in from your equation, and you would get this:

an = 30(n-1)2

6 0

3 years ago

One canned juice is 15% orange juice another 10% orange juice. How many liters of each should be mixed together in order to get

Delicious77 [7]

Equation:
0.15x + 0.10(5-x) = 0.11*5
---
Multiply thru by 100:
15x + 10*5 - 10x = 11*5

---
5x = 5
x = 1 liter (amt. 15% oj needed)
----
5-x = 4 liters (amt of 10% oj needed)
======

3 0

3 years ago

HELP MEEE W MATH ILL MARK

liq [111]

35 is your answer (I did it on a triangle calculator)

8 0

2 years ago

A television network is about to telecast a new television show. Before a show is launched, the network airs a pilot episode and

Basile [38]

Answer:

(E) 0.83

Step-by-step explanation:

We will solve it using conditional probability.

Let A be the event that a TV show is successful.

P(A) = 0.5

A' be event that the show is unsuccessful

P(A') =0.5

Let B be the event that the response was favorable

P(B) = 0.6

Let B' be the event that the response was unfavorable/

P(B') = 0.4

P(A∩B) = 0.5 and P(A∩B') = 0.3

We need to find new show will be successful if it receives a favorable response.

P(A/B) = $\frac{P(A∩B)}{P(B)}$

= 0.5/0.6

= 0.833

7 0

3 years ago

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Gnoma [55]

Answer:

Step-by-step explanation:

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2 years ago

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