3 years ago

How do you factor x4-x3-7x2-x+6?

1 answer:

5 0

$x^4-x^3-7x^2-x+6=x^4-x^3-6x^2-x^2-x+6=\\ \\=x^2(x^2-x-6)-(x^2-x-6)=(x^2-1)(x^2-x-6)=\\ \\=(x-1)(x+1)(x^2-3x+2x-6)=\\ \\=(x-1)(x+1)[x(x-3)+2(x-3)]=(x-1)(x+1)(x-3)(x+2)$

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Brrunno [24]

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Simplify terms:

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Use distributive property:

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3 years ago

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3 years ago

Which statement describes the translation of y = −1 over 5(x + 5)2 + 2 from standard position?

lesantik [10]

Answer:

Option B

Step-by-step explanation:

Given equation is

$y=\frac{-1}{5(x+5)^{2} } +2$

The original graph would be

$y=-\frac{1}{x^{2} }$

From this transformations done are

a) horizontal shift of 5 units to the left

b) shrink vertical by scale factor 1/5

c) vertical shift of 2 units up

Hence option A is not right

Option B is right.

Similarly C and D are not right.

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