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Darina [25.2K]
3 years ago
11

Discuss how the primary colors of light differ from the primary pigment colors

Physics
1 answer:
Bad White [126]3 years ago
6 0
The shades are very different
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A circular plate of 500-mm diameter is maintained at T1 = 600 K and is positioned coaxial to a conical shape. The back side of t
drek231 [11]
For part a)
Since the conical surface is not exposed to the radiation coming from the walls only from the circular plate and assuming steady state, the temperature of the conical surface is also equal to the temperature of the circular plate. T2 = 600 K

For part b)
To maintain the temperature of the circular plate, the power required would be calculated using:
Q = Aσ(T₁⁴ - Tw⁴)
Q = π(500x10^-3)²/4 (5.67x10^-8)(600⁴ - 300⁴)
Q = 5410.65 W
5 0
3 years ago
It takes 160 kj of work to accelerate a car from 24.0 m/s to 27.5 m/s. what is the car's mass?
ankoles [38]
Work-Energy :W = 1/2 m ( Vf^2 -Vo^2 )
Vo = 24.0 m/s Initial speed 
 Vf = 27.5 m/s  Final speed 

W = 1/2 m ( Vf^2 -Vo^2 )
160 kj = 1/ 2 m ( 27.5^2  -24.0 ^2)
160kj =  4680 x m
convert kilo joules to jeoules                     160000 j = 4689 xm
m = 160000 j/4689
m = 34.18 kg
4 0
3 years ago
HELP ASAP‼️<br><br> Can someone please answer this question I’m confusion❔
klemol [59]

the enclosed may help. earth rotes and you and i are fixed to it. air flows it's own path ...

3 0
3 years ago
The mass of a star is 1.61·1031 kg and its angular velocity is 1.60E-7 rad/s. Find its new angular velocity if the diameter sudd
Tcecarenko [31]

Answer:

ω₂ = 1.9025 x 10⁻⁶ rad/s

Explanation:

given,

mass of star = 1.61 x 10³¹ kg

angular velocity = 1.60 x 10⁻⁷ rad/s

diameter suddenly shrinks = 0.29 x present size

      r₂  = 0.29 r₁

using conservation of angular momentum

I₁ ω₁ = I₂ ω₂

(\dfrac{2}{5}mr_1^2)\omega_1=(\dfrac{2}{5}mr2^2)\omega_2

r_1^2\times \omega_1=r_2^2\times \omega_2

r_1^2\times 1.60\times 10^{-7}=(0.29r_1)^2\times \omega_2

1.60\times 10^{-7}=0.0841\times \omega_2

\omega_2=\dfrac{1.60\times 10^{-7}}{0.0841}

   ω₂ = 1.9025 x 10⁻⁶ rad/s

5 0
3 years ago
A bomb is dropped from a bomber traveling at the speed of 120 km / h, destroying a military objective located at a distance of 2
schepotkina [342]

Answer:

18 km

Explanation:

Convert km/h to m/s:

120 km/h × (1000 m/km) × (1 h / 3600 s) = 33.3 m/s

The time it takes the bomb to travel the 2000 meters is:

2000 m / (33.3 m/s) = 60 s

So it takes 60 seconds for the bomb to fall.  The distance it fell is therefore:

Δy = v₀ᵧ t + ½ aᵧ t²

Δy = (0 m/s) (60 s) + ½ (10 m/s²) (60 s)²

Δy = 18,000 m

Δy = 18 km

7 0
3 years ago
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