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Darina [25.2K]
3 years ago
11

Discuss how the primary colors of light differ from the primary pigment colors

Physics
1 answer:
Bad White [126]3 years ago
6 0
The shades are very different
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Why is fluorine special in terms of electronegativity?
Ahat [919]
Florine is special becaus Florine is at the highest value of electronegative value with 4.0
4 0
3 years ago
The power in an electrical circuit is given by the equation P = I2R, where I is the current flowing through the circuit and R is
kiruha [24]

Answer:

Explanation: Here we have given a direct equation . There for no need to worry .

P = I²×R

P = (12)² ×100

P = 14400W = 14.4 kW

For second one

P = I² ×R

200 = I²×150

I = √200/150

I = 1.15 A

5 0
3 years ago
A straight wire in a magnetic field experiences a force of 0.017 N when the current in the wire is 1.1 A. The current in the wir
mel-nik [20]

Answer:

The new current in the straight wire is 4.98 A

Explanation:

Given;

initial magnetic force on the wire, F₁ = 0.017 N

initial current flowing on the straight wire, I₁ = 1.1 A

When the current in the wire is changed,

new magnetic force on the wire, F₂ =  0.077 N

the new current in the wire, I₂ = ?

Applying equation of magnetic force on conductor;

F₁ = I₁BLsinθ

F₂ = I₂BLsinθ

BLsinθ  = F₁/I₁ = F₂/I₂

I₂ = (F₂I₁)/F₁

I₂ = (0.077 x 1.1) / 0.017

I₂ = 4.98 A

Therefore, the new current in the straight wire is 4.98 A

3 0
3 years ago
Running, swimming, and biking are what type of exercise aerobic or anaerobic
sesenic [268]
They are all cardiovascular exercises.
7 0
3 years ago
Read 2 more answers
A 6.50-g sample of copper metal at 25.0°C is heated by the addition of 84.0 J of energy. The final temperature of the copper is
Mekhanik [1.2K]

Answer:

Final temperature of the copper is 59 degrees Celsius

Explanation:

It is given that,

Mass of the sample of copper metal, m = 6.5 g

Initial temperature of the metal, T_i=25^{\circ}\ C=298\ K

Heat generated, Q = 84 J

The specific heat capacity of liquid water is 0.38 J/g-K

Let T_f is the final temperature of the copper. It can be calculated using the definition of specific heat of any substance. It is given by :

Q=mc\Delta T

Q=mc(T_f-T_i)

T_f=\dfrac{Q}{mc}+T_i

T_f=\dfrac{84}{6.5\times 0.38}+298

T_f=332\ K

or

T_f=59^{\circ}C

So, the final temperature of the copper is 59 degrees Celsius. Hence, this is the required solution.

4 0
3 years ago
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