Explanation:
It is given that,
Initial speed of the automobile, u = 65 km/hr =
Final speed of the automobile, v = 0
Deceleration of the automobile,
We need to find the distance covered by the car as it comes to rest. It can be calculated using third equation of motion as :
So, the acceleration of the car is . Hence, this is the required solution.
Answer:
<em>The speed of metal block B is 5 m/s after the collision</em>
Explanation:
<u>Law Of Conservation Of Linear Momentum
</u>
The total momentum of a system of bodies is conserved unless an external force is applied to it. The formula for the momentum of a body with mass m and velocity v is
P=mv.
If we have a system of bodies, then the total momentum is the sum of them all
If some collision occurs, the velocities change to v' and the final momentum is:
In a system of two masses, we have:
The metal block A has a mass of m1=3.2 Kg and moves at v1=4 m/s. Metal block b has a mass of m2=1.6 Kg and is initially at rest v2=0.
After the collision occurs, block A moves at v1'=1.5 m/s. We need to calculate the speed of the metal block B. Solving for v2':
Substituting the given values:
The speed of metal block B is 5 m/s after the collision
Answer:
Gravitational force will be 16 times more.
Explanation:
we know;
Gravitational force (F) = (Gm1m2)/d^2
when mass of each is doubled and distance between them is halved;
F= (G2m1×2m2)/(d/2)^2
=(4Gm1m2)/(d^2/4)
=4×4(Gm1m2)/d^2
=16(Gm1m2)/d^2
=16F
Answer:
Given:
Mass of oxygen (m) = 32.0 g = 0.032 kg
Volume occupied by oxygen (V) = 22.4 L = 0.0224 m³
Speed of sound in oxygen (v) = 317 m/s
To Find:
Bulk modulus of oxygen
Explanation:
The answer to the question is 1.5708~1.571.