Answer:
The effect of the angle between force and displacement on work.
Explanation:
When the angle between the force and displacement = zero , The work done is maximum when the direction of force is the same as the direction of displacement , such as a person pulling an object through a certain distance .
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In vacuum, all objects accelerate downward at 9.81 m/s^2 after release, and take the same time to fall the same distance.
If they're released together, they land together. It doesn't matter if one is a feather and the other is a school bus.
Answer:
b. 87N
Explanation:
Start by looking at the picture I attached you. As you can see in the diagram of the left, the weight=mg has one component in the x-axis and another in the y-axis. The normal force is directly over the y-axis, so we dont have to worry about the forces on the x-axis. Now, take a look at the diagram of the right, using it, we will be able to find the weight over the y-axis with trigonometry identities:
Now applying newton's second law:
There is no acceleration in this case, so a=0
Solving for N:
Answer:
(a) 2.23 m/s
(b) 0.9 m
Explanation:
h = 1 m, t = 0.1 second
horizontal component of initial velocity, ux = 2 m/s
vertical component of initial velocity, uy = 0
(a) Let v be the velocity after 0.1 seconds. Its vertical component is vy and horizontal component is vx.
The horizontal component of velocity remains constant as in this direction, acceleration is zero.
vx = ux = 2 m/s
Use first equation of motion in Y axis direction.
vy = uy + g t
vy = 0 + 9.8 x 0.1 = 0.98 m/s
Resultant velocity after 0.1 second
v^2 = vx^2 + vy^2
v^2 = 2^2 + 0.98^2
v = 2.23 m/s
(b) Let it takes time t to land.
Use second equation of motion along Y axis
h = uy t + 1/2 g t^2
1 = 0 + 1/2 x 9.8 x t^2
t = 0.45 second
Let it lan at a distance x.
so, x = ux x t
x = 2 x 0.45 = 0.9 m
<span>B. 30 degrees N or S latitude
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