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erik [133]
3 years ago
12

The coriolis effect causes winds to move in a ______ pattern.

Physics
2 answers:
natta225 [31]3 years ago
6 0

Answer:Curved

Explanation:

The Coriolis effect causes winds to move in a curved pattern.

for Example because of the Coriolis effect winds in Northern hemisphere appears to curved in right direction while in southern hemisphere it's effect is in opposite direction it tends to bend in left direction.

Andreyy893 years ago
5 0
I'm pretty sure The Coriolis effect causes winds to move in a circular pattern. 

Hope this helps!
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A force of 2 kN is applied to an object to make it move 3.6 m in the direction of the force. Select the correct value of work do
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W= F × d

W= 2kn × 3.6

W= 7.2 J

Work is measured in Joules!

4 0
3 years ago
If a pedestrian walked 900 meters forward and 300 meters back
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5 0
2 years ago
mass of the planet is 12 times that of earth and its radius is thrice that of earth , then find the escape velocity on that plan
Over [174]

Answer:

The escape velocity on the planet is approximately 178.976 km/s

Explanation:

The escape velocity for Earth is therefore given as follows

The formula for escape velocity, v_e, for the planet is v_e = \sqrt{\dfrac{2 \cdot G \cdot m}{r} }

Where;

v_e = The escape velocity on the planet

G = The universal gravitational constant = 6.67430 × 10⁻¹¹ N·m²/kg²

m = The mass of the planet = 12 × The mass of Earth, M_E

r = The radius of the planet = 3 × The radius of Earth, R_E

The escape velocity for Earth, v_e_E, is therefore given as follows;

v_e_E = \sqrt{\dfrac{2 \cdot G \cdot M_E}{R_E} }

\therefore v_e = \sqrt{\dfrac{2 \times G \times 12 \times M}{3 \times R} } =  \sqrt{\dfrac{2 \times G \times 4 \times M}{R} } = 16 \times \sqrt{\dfrac{2 \times G \times M}{R} } = 16 \times v_e_E

v_e = 16 × v_e_E

Given that the escape velocity for Earth, v_e_E ≈ 11,186 m/s, we have;

The escape velocity on the planet = v_e ≈ 16 × 11,186 ≈ 178976 m/s ≈ 178.976 km/s.

3 0
2 years ago
(b) Fig. 1.1 shows two airports A and C. north SE с sea land क WE not to scale Fig. 1.1 An aircraft flies due north from A for a
GalinKa [24]

The addition of vectors and the uniform motion allows to find the answers for the questions about distance and time are:

  • The distance to go between airports A and C  is 373.6 10³ m
  • The time to go from airport A to B is 2117 s

Vectors are quantities that have modulus and direction, so their addition must be done using vector algebra.

In this case the plane flies towards the North a distance of y = 360 10³ m at an average speed of v = 170 m / s, when arriving at airport B it turns towards the East and travels from x = 100 10³ m, until' it the distance reaches the airport C

Let's use the Pythagoras theorem to find the distance traveled

               R = Ra x² + y²

               R =   10³

               R = 373.6 10³ m

They indicate the average speed for which we can use the uniform motion ratio

               v = \frac{\Delta y }{t}

                t = \frac{\Delta y}{v}

They ask for the time in in from airport A to B, we calculate

                t = 360 10 ^ 3/170

                t = 2.117 10³ s

In conclusion we use the addition of vectors the uniform motion we can find the answer for the question of distance and time are:

  • The distance to go between airports A and C B is 373.6 10³ m
  • The time to go from airport A to B is 2117 s

Learn more here: brainly.com/question/15074838

5 0
2 years ago
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