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2 years ago

Solve the system by substitution or elimination

Mathematics

1 answer:

OleMash [197]2 years ago

4 0

X - y = 5,
x = 5 + y
substitute (x = 5 + y) into the first equation,
5 + y + 2y = -1
3y = -6
y = -2,
substitute y = -2 into (x - y = 5),
x + 2 = 5
x = 3

Hence, x = 3, y = -2

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What are the roots of the quadratic equation 2x2+7x+4=0? Select all that apply.

skad [1K]

Answer:

option A and B

$x=\frac{-7+\sqrt{17}} {4}$

and

$x=\frac{-7-\sqrt{17}} {4}$

Step-by-step explanation:

we have

$2x^2+7x+4=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$2x^2+7x+4=0$

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substitute in the formula

$x=\frac{-7\pm\sqrt{7^{2}-4(2)(4)}} {2(2)}$

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and

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2 years ago