We will use Boyle's law. P = 1/V which simply means pressure is inversely proportion to volume at a constant temperature. We will assume temperature here does not change. Since we have two pressure/volume points, we use this version of Boyle's law.
P1 V1 = P2 V2
P is pressure and V is volume
In our case:
P1 is 736, V1 is 4.2 while V2 is 9.0 but P2 is unknown. This is what we need to find out.
736 * 4.2 = P2 * 9.0
P2 = 736 * 4.2 / 9.0
P2 = 3091.2 / 9.0
P2 = 343.5
Therefore the new pressure 343 mm/hg
Here we see that the increase in volume causes decrease in pressure in total agreement with Boyle's law.
<u>Answer:</u> The concentration of 
in three significant figures will be 0.899 mol/L.
<u>Explanation:</u>
For the given reaction:
The above reaction follows zero order kinetics. The rate law equation for zero order follows:
![k=\frac{1}{t}([A_o]-[A])](https://tex.z-dn.net/?f=k%3D%5Cfrac%7B1%7D%7Bt%7D%28%5BA_o%5D-%5BA%5D%29)
where,
k = rate constant for the reaction = 
t = time taken = 10 sec
![[A_o]](https://tex.z-dn.net/?f=%5BA_o%5D)
= initial concentration of the reactant = 0.962 mol/L
[A] = concentration of reactant after some time = ?
Putting values in above equation, we get:
![6.28\times 10^{-3}=\frac{1}{10}(0.962-[A])](https://tex.z-dn.net/?f=6.28%5Ctimes%2010%5E%7B-3%7D%3D%5Cfrac%7B1%7D%7B10%7D%280.962-%5BA%5D%29)
![[A]=0.899mol/L](https://tex.z-dn.net/?f=%5BA%5D%3D0.899mol%2FL)
Hence, the concentration of in three significant figures will be 0.899 mol/L.
Answer:
13.1743
Explanation:
1 grams Calcium to mol = 0.02495 mol
