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e-lub [12.9K]
3 years ago
7

How would you calculate the difference in enthalpy?

Chemistry
1 answer:
Bad White [126]3 years ago
7 0
(Biology)
Equation: (delta)G = (delta)H - T (delta)S
(delta)G stand for change in free energy. When it is positive, it is endergonic. When it is negative, it is exergonic.
H stands for bond energy and is enthalpy
T is the absolute temperature expressed in the Kelvin scale
S is entropy or disorder in the system
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An ate or ite at the end of a compound name usually indicates that the compound contains___________.
Ymorist [56]

Answer:

D

Explanation:

According to IUPAC nomenclature, a negative polyatomic ion has its name ending in 'ate' or 'ite'

As in carbonate (CO3^2-)

Arsenite (AsO3-)

3 0
3 years ago
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How many moles of aluminum oxide (Al2O3) can be produced from 12.8 moles of oxygen gas (02)
zhannawk [14.2K]

Answer:

Theoretical Yield

Percent yield

Example stoichiometry problem

How much oxygen can be prepared from 12.25 g KClO3 . (Use molar mass KClO3 = 122.5 g.)

Most stoichiometry problems can be solved using the following steps.

Step 1.

Write and balance the equation for the decomposition of KClO3 with heat (∆). 2KClO3 + ∆ → 2KCl + 3O2

Step 2.

Convert what you have (in this case g KClO3) to moles.

# moles = grams/molar mass = 12.25 g /122.5 = 0.100 mole KClO3.

Step 3.

Using the coefficients in the balanced equation, convert moles of what you have (moles KClO3) to moles of what you want (in this case moles oxygen).

0.100 mol KClO3 x (3 moles O2/2 moles KClO3) = 0.100 x (3/2) = 0.150 mole O2.

Step 4.

Convert moles from step 3 to grams.

moles x molar mass = grams

0.150 mole O2 x (32.0 g O2/mole O2) = 4.80 g O2 produced from 12.25 g KClO3. This is the theoretical yield. If the ACTUAL yield is 4.20 grams, calculate percent yield. Percent yield = (actual yield/theoretical yield) x 100 = (4.20/4.80) x 100 = 87.5% yield

NOTE: In step 1, moles can be obtained other ways; in step 4 moles can be converted to other units.

a. For solutions, M x L = moles (or mL x M = millimoles).

b. For gases, L/22.4 = moles

4 0
3 years ago
11.<br> The electron configuration for phosphorous is [Ar]3s23p4.<br> TRUE<br> FALSE
user100 [1]

Answer:

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Explanation:

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5 0
2 years ago
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Alexandra [31]
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Hope this answers the question.
5 0
3 years ago
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Korvikt [17]

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Explanation:

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