Answer:
The magnitude of the vector A is <u>51 m.</u>
Explanation:
Given:
The horizontal component of a vector A is given as:
The vertical component of a vector A is given as:
Now, we know that, a vector A can be resolved into two mutually perpendicular components; one along the x axis and the other along the y axis. The magnitude of the vector A can be written as the square root of the sum of the squares of each component.
Therefore, the magnitude of vector A is given as:
Now, plug in 44.4 for , 25.1 for and solve for the magnitude of A. This gives,
Therefore, the magnitude of the vector A is 51 m.
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Answer:
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Explanation:
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Answer: 2,464m
Explanation:
Echo made by a source is dependent on the velocity of the sound in air/water, the distance between the source and the reflector and the time taken
Using the echo formula
2x = vt
Where x is the distance between the source and the reflector
v is the velocity of the sound in sea water is approximately= 1540m/s (This varies from place to place and depending on the season and nature of water)
t is the time taken
t = 3.20s
Substituting this datas into the equation to get 'x'
2x = 1540 × 3.20
x = 1540×3.20/2
x = 2,464m
The distance between the object creating the echo is 2,464m
Answer:
Explanation:
Path difference for the destructive interference of a single slit:
For the first - order minimum, n = 1, and
.........(1)
For the second - order minimum, n = 2, and
.........(2)
Dividing equation (2) by equation (1):