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liq [111]
2 years ago
13

To get employees to work longer hours, employers often offer __________ in the form of extra pay.

Physics
1 answer:
Dovator [93]2 years ago
6 0
C- Incentives it’s like a reward ~!
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What are two examples of common units for each of the above measurements
kap26 [50]

Density: g/mL, kg/cubic meter  

Volume: L, teaspoon  

Mass: g, MeV/sq. C

3 0
3 years ago
A radio station broadcasts its music with waves at a frequency of 7.34 x 10²Hz. These radio waves travel at a speed of 3.00x 10%
Lorico [155]

Answer:

See below

Explanation:

<u>I will use   3 x 10^8 m/s for speed or wave</u>

speed = wavelength * frequency

3 x 10^8  = w * 7.34 x 10^2     <====== are you sure this isn't KILO Hz ?

w = <u>408719. 3 meters   </u>

4 0
1 year ago
A ball is dropped off the balcony of a hotel room and it takes 2.8s to fall to the ground . how high above the ground is the bal
RideAnS [48]

The height of the ball above the ground is 38.45 m

First we will calculate the velocity of the ball when it touch the ground by using first equation of motion

v=u+gt

v=0+9.81×2.8

v=27.468 m/s

now the height of the ground can be calculated by the formula

v=√2gh

27.468=√2×9.81×h

h=38.45 m

5 0
2 years ago
A toaster draws 8 A of current with a voltage of 120 V. Which is the power used by the toaster?
dexar [7]
U=120 \text{ V}\\&#10;I=8\text{ A}\\&#10;P=U\cdot I\\\\&#10;P=120\cdot8=960 \text{ W}&#10;
7 0
3 years ago
A train starting from rest picks up a speed of 20 m/s in 20 s while travelling on a straight path. It continues to move at the s
Andrej [43]

Answer:

1300 m

Explanation:

As the path is straight, so the speed is equivalent to velocity. Now. assuming that the acceleration and deceleration of the train are constant. So, change of velocity with respect to time for acceleration as well as deceleration is constant. Hence, the slope of the speed-time graph is constant for the time of acceleration as well as deceleration. The speed for the time from 20 s to 70 s is constant, so slope for this interval of time is zero. The speed-time graph is shown in the figure.

The total distance covered by the train during the entire journey is the area of the speed-time graph.

Area=\frac{1}{2}(20\times 20)+ 50\times 20+\frac{1}{2}(20\times 10)

=200+1000+100

=1300

As velocity is in m/s and time is in s so the unit of area is m

Hence, the total distance is  1300m.

8 0
3 years ago
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