The answer is 20.4m in height. You can use the kinematics equation Vf^2=V0^2+2ad Therefore we have solving for d or height, we get d=Vf^2/2g
(20m/s)^2/(2*9.8m/s^2)=20.4m
Answer:(10.69, 11.436)
Explanation:
Given
initial height of ball is 2 m
height of basket is 3.05 m
Launching angle

y=1.05
equation of trajectory of ball is given by

for x=12.27

u=10.69
for x=11.73

u=11.436 m/s
Thus range of speed is (10.69, 11.436)
Answer:
change in entropy is 1.44 kJ/ K
Explanation:
from steam tables
At 150 kPa
specific volume
Vf = 0.001053 m^3/kg
vg = 1.1594 m^3/kg
specific entropy values are
Sf = 1.4337 kJ/kg K
Sfg = 5.789 kJ/kg
initial specific volume is calculated as





FROM STEAM Table
at 200 kPa
specific volume
Vf = 0.001061 m^3/kg
vg = 0.88578 m^3/kg
specific entropy values are
Sf = 1.5302 kJ/kg K
Sfg = 5.5698 kJ/kg
constant volume so




Change in entropy 
=3( 3.36035 - 2.88) = 1.44 kJ/kg
Sup Milk,
Sublimation = Energy is absorbed and a solid turns to a gas.
Condensation = Energy is released and a gas changes to a liquid.
Evaporation = Energy is absorbed into a liquid to turn it into a gas.