Explanation:
KE = q
½ mv² = mCΔT
ΔT = v² / (2C)
ΔT = (200 m/s)² / (2 × 236 J/kg/°C)
ΔT = 84.7°C
The current in the coil is 297 A
Explanation:
The magnetic field of a circular coil carrying a current is given by

where
is the vacuum permeability
N is the number of turns in the coil
I is the current in the coil
R is the radius of the coil
For the coil in this problem, we have:

R = 20 cm = 0.20 m
N = 15
Solving the equation for I, we find the current in the coil:

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Answer:
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Explanation:
Answer:
The answer is gravitational force
Explanation:
Answer:
26.822 m/s
Explanation:
60 mi/hr * 5280 ft/mile * 1 hr / 3600 sec * 12 in / foot * 1 meter / 39.37 in = <u>26.822 m/s</u>