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lesya [120]
3 years ago
15

Sami pops a helium balloon at a birthday party. What will happen to the particles of helium that were in the balloon?

Physics
1 answer:
Anit [1.1K]3 years ago
4 0

They will mix with air. Air consists mostly of nitrogen and oxygen but there are also traces of CO2 and noble gases in air, and helium is one of those noble gases.

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From the lens equation calculate the position of the following images produced by a convex lens.
fiasKO [112]

Explanation:

(i)

O is the object and I is the image.

The image formed is enlarged and it is erect. So the magnification will be positive (+) and greater than 1.

Refer above image. 1

(ii)

O is the object and I is the image.

The image formed is diminished and erect. So the magnification will be positive (+) and less than1.

Refer above image. 2

(iii)

The image will be formed as the 2F on the other side of the lens and it will be of same of the object.

5 0
3 years ago
A homeowner uses a snowblower to clear his driveway. knowing that the snow is discharged at an average angle of 40° with the hor
Nesterboy [21]

given that snow is projected at an angle of 40 degree

It range is given as a = 19 ft

a = 19 * 0.3048 = 5.8 m

now we can use the formula of horizontal range

R = \frac{v_o^2 sin2\theta}{g}

5.8 =\frac{ v_o^2 sin(2*40)}{9.8}

5.8 = \frac{v_o^2 * sin80}{9.8}

v_o^2 = 57.7

v_o = 7.6 m/s

<u>so its initial speed must be 7.6 m/s</u>

8 0
3 years ago
Physical quantity are measurable quantities
Vilka [71]

Answer:

yeah physical quantities are the quantities which can be meaured

7 0
3 years ago
The energy required to ionize magnesium is 738 kj/mol. What minimum frequency of light is required to ionize magnesium
Cerrena [4.2K]

Answer:

The minimum frequency required to ionize the photon is 111.31 × 10^{37} Hertz

Given:

Energy = 378 \frac{kJ}{mol}

To find:

Minimum frequency of light required to ionize magnesium = ?

Formula used:

The energy of photon of light is given by,

E = h v

Where E = Energy of magnesium

h = planks constant

v = minimum frequency of photon

Solution:

The energy of photon of light is given by,

E = h v

Where E = Energy of magnesium

h = planks constant

v = minimum frequency of photon

738 × 10^{3} = 6.63 × 10^{-34} × v

v = 111.31 × 10^{37} Hertz

The minimum frequency required to ionize the photon is 111.31 × 10^{37} Hertz


7 0
3 years ago
Read 2 more answers
The Parliament Building tower clock in London, has hour and minute hands with lengths of 2.70 m and 4.50 m and masses of 60.0 kg
KATRIN_1 [288]

Answer:

Explanation:1.1993 kg-m^2/s

Given

length of hour hand is 2.7m

length if minute hand is 4.5m

And Moment of inertia of a rod about its one of a end I=\frac{ml^2}{3}

\omegafor hour hand is

\omega =\frac{2\pi }{12\cdot 3600} rad/s

Angular speed for minute hand =frac{2\pi }{3600}

Angular moment(L) is given I\omega

L_{minute}=\frac{100\times 4.5^2}{3}\times frac{2\pi }{3600}

L_{minute}=1.178

For hour hand

L_{hour}=\frac{ml^2}{3}\omega

L_{hour}=\frac{60\times 2.7^2}{3}\times \frac{2\pi }{12\cdot 3600}

L_{hour}=0.0212 kg-m^2/s

L_{total}=1.1993 kg-m^2/s

7 0
3 years ago
Read 2 more answers
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