A small block has constant acceleration as it slides down a frictionless incline. The block is released from rest at the top of
1 answer:
Answer:
2.58 m/s
Explanation:
We can use the following equation of motion to find out the constant acceleration of the block:
where v = 3.8 m/s is the final velocity after it has traveled 7.4 m, is the initial velocity of the block when it starts from rest, , and
is the distance traveled.
We can use the same motion equation to calculate block speed at the end of 3.4m track
You might be interested in
There are already 2 givens, hence we can do direct substitution to get the answer. To make the process simpler, derive the distance formula from the Work formula.
Work = Force x Distance
Distance =
Work is 450J while the force is 150N hot tub
To get the proper units, get the equivalent of Joule to eliminate newton. A joule Is equal to 1 N-m
Distance =
Distance = 3m
Hence, the hot tub is lifted 3 meters.
Work = Force x Distance
Distance =
Work is 450J while the force is 150N hot tub
To get the proper units, get the equivalent of Joule to eliminate newton. A joule Is equal to 1 N-m
Distance =
Distance = 3m
Hence, the hot tub is lifted 3 meters.
Answer:
First option
Explanation:
If the ball is running in a circular motion then its velocity <em>v</em> will be tangency to the circular path.
In this problem the centripetal force that allows the circular movement is the tension <em>T</em> of the rope to which the ball is tied, if the child releases the rope then this tension becomes equal to zero and the circular movement is interrupted.
As the speed <em>v</em> of the ball is always tangential to the circumference at any point of the same, then at the instant in which the rope is released, the ball will follow the same trajectory that it had at that moment, that is, tangential to the circumference.
Observe the attached image.
Therefore the answe is: tangent to the circle
