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3 years ago

WEATHER: What kind of weather occurs along this type of front?

Physics

2 answers:

Radda [10]3 years ago

4 0

Cold front because the warm front or hit front is lower on the right and goes downwards and cold front is in the middle and goes to Minneapolis

konstantin123 [22]3 years ago

3 0

Answer:

Cold front because the warm front or hit front is lower on the right and goes downwards and cold front is in the middle and goes to Minneapolis

Explanation:

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A 20 kg wagon is pulled along the level ground by a rope inclined at 30 degree above the horizontal. A friction force of 30 N op

Elan Coil [88]

(a) 34.6 N

To solve the problem, we have to analyze the forces acting along the horizontal direction.

We have:

- Forward: the component of the pull parallel to the ground, which is

$F cos \theta$

where

F is the magnitude of the pull

$\theta=30^{\circ}$ is the angle

- Backward: the force of friction, which is

$F_f = 30 N$

So, the equation of motion is

$F cos \theta - F_f = ma$

where

m = 20 kg is the mass of the wagon

a is the acceleration

In this part, the wagon is moving at constant speed, so a =0 and the equation becomes

$F cos \theta - F_f = 0$

Therefore, we can find the pulling force:

$F=\frac{F_f}{cos \theta}=\frac{30}{cos 30}=34.6 N$

(b) 43.9 N

In this case, the acceleration is

$a=0.40 m/s^2$

So, the equation of motion in this case is

$F cos \theta - F_f = ma$

So this time we have to take into account the term (ma).

Using the same data as before:

m = 20 kg

$\theta=30^{\circ}$

$F_f = 30 N$

We find the new magnitude of F:

$F=\frac{ma+F_f}{cos \theta}=\frac{(20)(0.40)+30}{cos 30}=43.9 N$

6 0

3 years ago

A bubble, located 0.200 m beneath the surface in a glass of beer, rises to the top. The air pressure at the top is 1.01x10⁵ Pa.

Cerrena [4.2K]

Answer:

$\frac{1.019}{1}$

Explanation:

To solve this equation we will have to consider that the bubble is filled with an Ideal Gas and as such we can use the Ideal Gas Law

$PV = nRT$

Where

$P$ = Pressure

$V$ = Volume

$n$ = Moles

$R$ = Ideal Gas Constant

$T$ = Temperature

Now since we know that the value for the temperature and moles is constant we can simply use Boyles Law for the two states

$P_{1} V_{1} =P_{2} V_{2}$

Let us look at the two states

State 1 (at top)

Pressure = $1.01*10^5$

Volume = $V_{1}$

State 2 (at bottom)

Pressure = $1.01*10^5 + dgh$

Where

$d$ = Density of liquid (1000 kg/m³)

$d$ = Acceleration due to gravity (9.8 m/s²)

$d$ = Height of liquid (0.200 m)

Pressure = $102,962$

Volume = $V_{2}$

Inputting these values into the Boyles Law

$P_{1} V_{1} =P_{2} V_{2}\\ (101000)V_{1} = (102962)V_{2}\\ \frac{V_{1}}{V_{2}} = \frac{102962}{101000} \\ \frac{V_{1}}{V_{2}} = \frac{1.019}{1}$

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3 years ago

The bond enthalpy value for a carbon to hydrogen bond is 413 kJ. What does this mean?

AlladinOne [14]

Breaking bond requires energy. The bond between the carbon and hydrogen is broken when the energy is absorbed. The enthalpy is defined to be the energy taken to break the one mole of the stated carbon and hydrogen bond. Thus a should be the correct answer

6 0

4 years ago

Read 2 more answers

1:A pattern or grouping of stars that people imagine representing a figure, an animal or an object.

Nesterboy [21]

Answer:

1.constellation
2.Probably a dwarf planet

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3 years ago

What force does it take to accelerate a 7.2 kg object 3.0 m/s^2.

grin007 [14]

Answer:

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 7.2 × 3 = 21.6

We have the final answer as

Hope this helps you

3 0

2 years ago