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inna [77]
3 years ago
9

How does gravity relate to potential energy?

Physics
2 answers:
ozzi3 years ago
7 0

Answer:

PE uses the acceleration of gravity in its calculation definition

Explanation:

Potential Energy = mass * <u>acceleration of gravity</u> * height

Nookie1986 [14]3 years ago
3 0

Answer:

the potential energy a massive object has in relation to another massive object due to gravity

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If a farsighted person has a near point that is 0.600 mm from the eye, what is the focal length f2f2f_2 of the contact lenses th
Readme [11.4K]

Answer:

0.22mm

Explanation:

A far sighted person is a person suffering from long sightedness i.e such individual can only see far distant object clearly but not near distant object. The defect is corrected using convex lens.

Since convex lens is used, the focal (f) length of the lens is positive and the image distance (v) is also positive.

Using the lens formula,

1/f = 1/u + 1/v

Where u is the object distance = 0.35mm

v = 0.6mm

1/f = 1/0.35+1/0.6

1/f = 2.86 + 1.67

1/f = 4.53

f = 1/4.53

f = 0.22mm

The focal length of the contact lenses will be 0.22mm

5 0
3 years ago
An Olympic high jumper, with a mass of 82 kg, has a
Digiron [165]

Answer:

I don't really know

Explanation:

I really wanted to help you, but then I realized i didnt know how to

8 0
3 years ago
a 10kg cement block horizontally at 6 m/s plows into a bank of sand and comes to a stop in 2.0 m/s. What is the average impact f
Gnesinka [82]
I assume the block plows into the bank of sand with a velocity of 6 m/s and comes to a stop in 2 s.

\bar Ft =  \Delta mv  \\  \\  \bar F =  \frac{\Delta mv }{t}  \\  \\  \bar F \ avarage \ Force \\  m \ momentum \\ v \ velocity \\ t \ time
7 0
4 years ago
A 5.00 gram bullet moving at 600 m/s penetrates a tree trunk to a depth of 4.00 cm.
Crazy boy [7]
A) Work energy relation;
 Work =ΔKE ; work done = Force × distance, while, Kinetic energy = 1/2 MV²
 F.s = 1/2mv²
F× 4×10^-2 = 1/2 × 5 ×10^-3 × (600)²
 F = 900/0.04
    = 22500 N
Therefore, force is 22500 N

b) From newton's second law of motion;
 F = Ma
Thus; a = F/m
             = 22500/(5×10^-3)
             = 4,500,000 m/s²
But v = u-at
  0 = 600- 4500,000 t
t = 1.33 × 10^-4 seconds
6 0
4 years ago
a bicycle uniformly from rest at time t the velocity of the bicycle is v at what time will the bicycle have a velocity of 4v​
sesenic [268]

Here

  • Acceleration and initial velocities are constant.

According to first equation of kinematics.

\\ \sf\longmapsto v=u+at

\\ \sf\longmapsto v=0+at

\\ \sf\longmapsto v=at

\\ \sf\longmapsto v\propto t

  • Time was t at velocity v
  • Time will be 4t at velocity 4v
7 0
3 years ago
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