Kinetic energy than parked
Answer:
Explanation:
Given that,
A point charge is placed between two charges
Q1 = 4 μC
Q2 = -1 μC
Distance between the two charges is 1m
We want to find the point when the electric field will be zero.
Electric field can be calculated using
E = kQ/r²
Let the point charge be at a distance x from the first charge Q1, then, it will be at 1 -x from the second charge.
Then, the magnitude of the electric at point x is zero.
E = kQ1 / r² + kQ2 / r²
0 = kQ1 / x² - kQ2 / (1-x)²
kQ1 / x² = kQ2 / (1-x)²
Divide through by k
Q1 / x² = Q2 / (1-x)²
4μ / x² = 1μ / (1 - x)²
Divide through by μ
4 / x² = 1 / (1-x)²
Cross multiply
4(1-x)² = x²
4(1-2x+x²) = x²
4 - 8x + 4x² = x²
4x² - 8x + 4 - x² = 0
3x² - 8x + 4 = 0
Check attachment for solution of quadratic equation
We found that,
x = 2m or x = ⅔m
So, the electric field will be zero if placed ⅔m from point charge A, OR ⅓m from point charge B.
Answer:
U can walk to the bathroom
Explanation:
This definitely has to do with erosion. We can expect that the statue will weather faster because of more surface area.I hope this is what you were looking for
Answer:
Width = 680 [m]
Explanation:
To solve this problem we must know the speed of sound in the air, conducting an internet search, we find that this speed has a value of v = 340 [m/s].
We apply the following kinematic equation, which relates space to time, to define speed.
v = x /t
where:
x = distance [m]
t = time [s]
v = velocity [m/s]
Now replacing:
x = 340 * 4
x = 1360 [m]
But the width of the cannon is calculated when the sound wave hits the wall of the canyon, so this width is half the distance.
Width = 1360 / 2 = 680 [m]