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adell [148]
3 years ago
12

A gas is initially at a pressure of 0.43 atm, and a volume of 11.7 liters. Then the pressure is raised to 3.61 atm and the volum

e is decreased to 9.5 liters. This causes the temperature to raise to 627 K. What was the initial temperature of the gas? A. 83.19 K B. 7.32 K C. 327.97 D. 91.98 K
Chemistry
2 answers:
lukranit [14]3 years ago
4 0

Answer:

D. 91.98K

Explanation:

The General Gas Law equation is given by,

\frac{P_1V_1}{T_1}  =  \frac{P_2V_2}{T_2}

From the question,

the initial pressure,

P_1 = 0.43 \: atm

the initial volume,

V_1 = 11.7 \: litres

the final temperature,

T_2=627K

the final pressure,

P_2=3.61atm

the final volume,

V_2=9.5litres

Making

T_1

the subject of the expression, we obtain

T_1= \frac{P_1V_1T_2}{P_2V_2}

By substitution,

T_1= \frac{0.43 \times11.7 \times627}{3.61 \times9.5}

T_1=91.980K

Hence the initial temperature was 91.98 K

olga_2 [115]3 years ago
4 0

The Initial temperature was 92.24 K

<h2>Further Explanation;</h2><h3>Boyle's law </h3>
  • Boyle's law states that the volume of a fixed mass of a gas is inversely proportional to its pressure at a constant temperature.
  • That is;

P\alpha \frac{1}{V}

P = \frac{k}{V}, where k is a constant

Charles' Law

  • Charles's law states that the volume of a fixed mass of a gas is directly proportional to absolute temperature at constant pressure.
  • That is; V \alpha T\\ V= kT, where k is a constant
<h3>Combined gas law</h3>
  • Combined gas law combines both Boyle's law and Charles's law.
  • It states that the volume of a fixed mass of a gas is directly proportional to absolute temperature and inversely proportional to pressure.

That is;

\frac{P_{1}V_{1}  }{T_{1} } = \frac{P_{2}V_{2}  }{T_{2} }

Given;

P_{1} = 0.43 atm\\ V_{1} =11.7 liters\\ T_{1} = ?

While;

P_{2} = 3.61 atm\\ V_{2} =9.5 liters \\ T_{2} =627 K

To calculate T_{1}

T_{1} =\frac{P_{1}V_{1}T_{2}}{P_{2}V_{2}}

T_{1} =\frac{(0.43 atm)(11.7 l)(627 K)}{(3.61 atm)(9.5 L)}

               T_{1} =92.24 K

Therefore the initial temperature is 92.24 K

Keywords: Combined gas laws, Boyle's law and Charles's law

<h3>Learn more about:</h3>
  • Boyles’s law: brainly.com/question/1158880
  • Gay-Lussac’s law: brainly.com/question/2438000
  • Charles’s law:brainly.com/question/2438000
  • Combined gas law: brainly.com/question/2441061

Level: High school

Subject: Chemistry

Topic: Gas laws

Sub-topic: Combined gas laws

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