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4 years ago

Help me please with the one that are circled

Mathematics

2 answers:

mario62 [17]4 years ago

8 0

5.the answer is 333. I don’t know the rest

ELEN [110]4 years ago

8 0

Answer:i know the answer i get cant really see the the picturre thake a better picture

Step-by-step explanation:

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24+3x=3x+3(7-1) What does x equal? Please show me how to do it I don't want the answer. (Well I do but show me how to get it als

balandron [24]

24 + 3x = 3x + 3(7 - 1)

Eliminate the parentheses: 24 + 3x = 3x + 3(6)

24 + 3x = 3x + 18

Subtract 3x from each side: 24 = 18

Look at that for a second. Can ANY value of 'x' make 24 equal to 18 ?
I don't think so.
There's NO number that makes the equation a true statement.

That's just another way to say: "The equation has NO solution."

5 0

4 years ago

ABC is a right-angled triangle.

IrinaK [193]

Answer:

10.83

Step-by-step explanation:

AB=18Xsin(37 °)

=10.83

7 0

3 years ago

What are the domain and range of the function f(x) = 3x 5?.

Bingel [31]

The domain and range of the given function both are the real numbers.

<h2>Given that:</h2>

The domain and range of function f(x) = 3x + 5 has to be found.

<h2>Explanation for domain and range:</h2>

Considering working in real numbers, domain is $\mathbb{R}$ and range is $\mathbb{R}$ too.

Domain can be complex numbers too, but for the sake of daily life cases, we consider working in real numbers.

Thinking of it as equation of straight line can help.

The given function is monotonically increasing and continuous.

Thus Range can be calculated as interval ( f(min value of domain), f(max value of domain) ) which gives us $\mathbb{R}$ as range.

Below is the plot of f(x) = 3x + 5 in real number plane.

In fact, any linear equation of the form

$y = mx + c ; \: \: c \in R \: and \: m \in {R-\{0\}}$

has both domain and range as real numbers.

For more information, refer to:

brainly.com/question/12208715

7 0

3 years ago

Read 2 more answers

Three populations have proportions 0.1, 0.3, and 0.5. We select random samples of the size n from these populations. Only two of

IRINA_888 [86]

Answer:

(1) A Normal approximation to binomial can be applied for population 1, if n = 100.

(2) A Normal approximation to binomial can be applied for population 2, if n = 100, 50 and 40.

(3) A Normal approximation to binomial can be applied for population 2, if n = 100, 50, 40 and 20.

Step-by-step explanation:

Consider a random variable X following a Binomial distribution with parameters n and p.

If the sample selected is too large and the probability of success is close to 0.50 a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

np ≥ 10
n(1 - p) ≥ 10

The three populations has the following proportions:

p₁ = 0.10

p₂ = 0.30

p₃ = 0.50

(1)

Check the Normal approximation conditions for population 1, for all the provided n as follows:

$n_{a}p_{1}=10\times 0.10=1$

Thus, a Normal approximation to binomial can be applied for population 1, if n = 100.

(2)

Check the Normal approximation conditions for population 2, for all the provided n as follows:

$n_{a}p_{1}=10\times 0.30=310\\\\n_{c}p_{1}=50\times 0.30=15>10\\\\n_{d}p_{1}=40\times 0.10=12>10\\\\n_{e}p_{1}=20\times 0.10=6$

Thus, a Normal approximation to binomial can be applied for population 2, if n = 100, 50 and 40.

(3)

Check the Normal approximation conditions for population 3, for all the provided n as follows:

$n_{a}p_{1}=10\times 0.50=510\\\\n_{c}p_{1}=50\times 0.50=25>10\\\\n_{d}p_{1}=40\times 0.50=20>10\\\\n_{e}p_{1}=20\times 0.10=10=10$

Thus, a Normal approximation to binomial can be applied for population 2, if n = 100, 50, 40 and 20.

8 0

3 years ago

David started across a lake 15 miles wide in his fishing boat at 10 miles per hour. He had to row the rest of the way at only 5

schepotkina [342]

Answer:

Total time = 2hrs

Step-by-step explanation:

Firstly, to outline some variables, with which we can construct some equations:

x = the time taken to cross the river at 10mph (in hrs)

y = the time taken to cross the river at 5mph (in hrs)

t = total time taken to cross the river (in hrs)

a = distance travelled at speed 10mph (in miles)

b = distance travelled at speed 5mph (in miles)

Then,

a + b = 15

t = x + y

y = ¹/₂(t) ∴ t = 2y, so,

x + y = 2y ∴ x = y

Secondly, we know speed = distance/time, so,

10 = a/x ⇒ x = a/10

5 = b/x ⇒ x = b/5

So,

a/10 = b/5 ∴ a = 2b

Thirdly, if a + b = 15, then,

2b + b = 15 ⇒ 3b = 15 ⇒ b = 5

[a = 2b ∴ a = 10]

Fourthly, x = b/5, so,

x = 5/5 = 1,

Since x = y, y = 1 and since t = 2y,

t = 2(1) = 2

The whole trip, therefore, took 2hrs.

5 0

3 years ago