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Aloiza [94]
3 years ago
12

What is the molar concentration of 5% acetic acid?

Chemistry
1 answer:
larisa [96]3 years ago
3 0

Answer:Vinegar Is 5% Acetic Acid And Its Molarity Is 0.833M.

Explanation:

yes

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What is the h concentration in a solution with a ph of 1.25
lyudmila [28]

Answer:

0.056 M

Explanation:

To calculate the concentration of h we must use the following formula:

10^-pH

So lets plug in our pH:

10⁻¹.²⁵

When we plug this into our calculator our answer is

0.056 M

5 0
3 years ago
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Oil is more dense than water. How will this affect the weight of objects that will float on it?
horrorfan [7]
Oil is more dense than alcohol, but less dense than water. The molecules that make up the oil are larger than those that that make up water, so they cannot pack as tightly together as the water molecules can. They take up more space per unit area and are less dense.
3 0
3 years ago
.If a 20kg bicycle at the bottom of a hill has speed of 25m/s, how high can the cart go up the hill?
frez [133]
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4 0
3 years ago
What concentrations of acetic acid (pKa = 4.76) and acetate would be required to prepare a 0.15 M buffer solution at pH 5.0? Not
Leni [432]

Answer:

Acetic acid 0,055M and acetate 0,095M.

Explanation:

It is possible to prepare a 0,15M buffer of acetic acid/acetate at pH 5,0 using Henderson-Hasselblach formula, thus:

pH = pka + log₁₀ [A⁻]/[HA] <em>-Where A⁻ is acetate ion and HA is acetic acid-</em>

Replacing:

5,0 = 4,76 + log₁₀ [A⁻]/[HA]

<em>1,7378 =  [A⁻]/[HA] </em><em>(1)</em>

As concentration of buffer is 0,15M, it is possible to write:

<em>[A⁻] + [HA] = 0,15M </em><em>(2)</em>

Replacing (1) in (2):

1,7378[HA] + [HA] = 0,15M

2,7378[HA] = 0,15M

[HA] = 0,055M

Thus, [A⁻] = 0,095M

That means you need <em>acetic acid 0,055M</em> and <em>acetate 0,095M</em> to obtain the buffer you need.

i hope it helps!

7 0
3 years ago
You have a 1.153 g sample of an unknown solid acid, HA, dissolved in enough water to make 20.00 mL of solution. HA reacts with K
seropon [69]

Answer:

HA +  KOH  →  KA  +  H₂O

Explanation:

The unknown solid acid in water can release its proton as this:

HA  +  H₂O  →  H₃O⁺  +  A⁻

As we have the anion A⁻, when it bonded to the cation K⁺, salt can be generated, so the reaction of HA and KOH must be a neutralization one, where you form water and a salt

HA +  KOH  →  KA  +  H₂O

It is a neutralization reaction because H⁺ from the acid and OH⁻ from the base can be neutralized as water

7 0
3 years ago
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